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2 years ago

Reflect (−1,7) in the x-axis followed by the y-axis.

Mathematics

2 answers:

Ahat [919]2 years ago

8 0

X axis (-1,-7) y axis (1,-7)

vekshin12 years ago

6 0

Over the x-axis (-1,-7) nd that across the y-axis is (1,-7)

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A loan company charges $30 interest <br />for a one month loan of $500. Find the annual interest they are charging

xz_007 [3.2K]

Answer:

$360

Step-by-step explanation:

If the company charges $30 for $500 in one month.

The interest they will be changing for a year = 30*12 = $360 interest.

It's just simple, multipling the the interest value by 12 to get it's annual interest value.

4 0

3 years ago

A company buys pens at the rate of $7.50 per box for the first 10 boxes, $5.50 per box for the next 10 boxes, and $4.50 per box

photoshop1234 [79]

So it is really easy to solve firstly we can see how much does the first 10 boxes make which makes around 75$ obviously. Secondly 55$ for the next 10 boxes.

So for now we can simply calculate that we have spent around 130$ which means 20 boxes. The remaining money left is 18$ so we can buy 18/4.5 = 4 only 4 boxes with that money. Hence a total of 24 boxes.

4 0

3 years ago

The total cost (in hundreds of dollars) to produce x units of a product is c(x) = (3x-2) / (8x+1), find the average cost for eac

olya-2409 [2.1K]

Answer:

a) $\frac{74}{10025}$

b) $\frac{3x-2}{x(8x+1)}$

c) $\frac{-24x^2+32x-2}{(8x^2+x)^2}$

Step-by-step explanation:

For total cost function $c(x)$ , average cost is given by $\frac{c(x)}{x}$ i.e., total cost divided by number of units produced.

Marginal average cost function refers to derivative of the average cost function i.e., $\left ( \frac{c(x)}{x} \right )'$

Given: $c(x)=\frac{3x-2}{8x+1}$

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

At x = 50 units,

$\frac{c(50)}{50}=\frac{150-2}{50(400+1)}=\frac{148}{50(401)}=\frac{74}{10025}$

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

Marginal average cost:

Differentiate average cost with respect to $x$

Take $f=3x-2\,,\,g=8x^2+x$

using quotient rule, $\left ( \frac{f}{g} \right )'=\frac{f'g-fg'}{g^2}$

Therefore,

$\left ( \frac{c(x)}{x} \right )'=\left ( \frac{3x-2}{8x^2+x} \right )'\\=\left ( \frac{3(8x^2+x)-(16x+1)(3x-2)}{(8x^2+x)^2} \right )\\=\frac{24x^2+3x-48x^2-3x+32x+2}{(8x^2+x)^2}\\=\frac{-24x^2+32x-2}{(8x^2+x)^2}$

3 0

3 years ago

Simplify the expression:<br> sinx+cosx/sinxcosx

Keith_Richards [23]

Sin x + $\frac{cos x}{sinx cosx}$
= sinx + $\frac{1}{sin x}$
= $sin^{2}x$ +1
= $cos^{2} x$

6 0

3 years ago

**PLEASE HELP ASAP** Terri is analyzing a circle, y^2 + x^2 = 36, and a linear function g(x). Will they intersect?

Alborosie

We analyze the linear function to find that it has equation $y=x$ . Drawing the line, we find that it will intersect the circle at negative and positive x-coordinates.

We can prove this by substituting $y=x$ into the given equation:

$x^2+x^2=36$

$2x^2=36$

$x^2 = 18$

$x = \pm 3\sqrt{2}$

Hence, $x = 3\sqrt{2}$ or $-\sqrt{2}$ , so there are both positive and negative values for $x$ .

5 0

3 years ago