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sdas [7]
3 years ago
10

A satellite television company charges a one-time installation fee and

Mathematics
2 answers:
stiv31 [10]3 years ago
8 0
The answer is 2 y= total installation cost. x is the variable representing the number of months of service and $40 is the fixed price while $90 is dependent on the xvalue
romanna [79]3 years ago
4 0

Answer:

Option (2).

Step-by-step explanation:

A satellite T.V. company charges one time installation fees along with monthly service charge.

Total cost is modeled by the function y = 40 + 90x

Here y = Total cost charged by the company

A one time installation charges = $40

Service charge for a month = $90

and number of months for which service was used = x months

Therefore, Option (2) explains the function well.

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A population of 25 rabbits on a farm have a growth rate of 2 rabbits every month. Write the exponential function. How many rabbi
enot [183]
Y=mx+b plus 900 rabbits
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3 years ago
8<br> m_AHI = 13x +9, mZGHI = 137°,<br> and mZGHA = 8x + 2. Find x.<br> H<br> G
777dan777 [17]

Answer:

x = 6

Step-by-step explanation:

<GHA + <AHI = <GHI

(8x + 2) + (13x + 9) = 137

8x + 13x + 2 + 9 = 137

21x= 137 - 11

x = 126/21

x = 6

3 0
3 years ago
I know the answer I got is wrong help.
irinina [24]

Answer:

∠2 = 18°

Step-by-step explanation:

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72 = 4∠2 ( divide both sides by 4 )

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8 0
3 years ago
10 POINTS
podryga [215]
Take the length of the larger divide it by the smaller

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6 0
3 years ago
Read 2 more answers
A Rasmussen Reports survey of 1,000 US adults found that 42% believe raising the minimum wage will help the economy. Construct a
vitfil [10]

Answer:

(0.3798, 0.4602)

Step-by-step explanation:

Let p be the true proportion of US adults who believe raising the minimum wage will help the economy. A point estimate for p is \hat{p}=0.42 and a good aproximation (because we have a large sample) for the standard deviation of \hat{p} is \sqrt{\hat{p}(1-\hat{p})/n}=\sqrt{0.42(0.58)/1000}=0.0156. Therefore, a 99% confidence interval for p is given by \hat{p}\pm z_{\alpha/2}\sqrt{\frac{\hat{p}(1-\hat{p})}{n}} where \alpha=0.01 and z_{\alpha/2} is the \alpha/2th quantile of the standard normal distribution, so we have, 0.42\pm z_{0.005}0.0156, i.e., 0.42\pm(-2.5758)(0.0156) or equivalently (0.3798, 0.4602).

6 0
3 years ago
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