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Trava [24]
2 years ago
9

Which expression is equivalent to (x'2-2)'5​

Mathematics
1 answer:
Greeley [361]2 years ago
3 0

Answer: D = x'10 − 10x'8 + 40x'6 − 80x'4 + 80x'2 − 32

Step-by-step explanation:

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Step-by-step explanation:

The shape is a trapezoid

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A=\frac{base_{1} +base_{2} }{2} h

A=\frac{10+14}{2} *5\\A=12*5\\A=60

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D=\sqrt{(x_{2} -x_{1}) ^{2}+(y_{2}-y_{1})  ^{2}

Q( -4,4)  B (-2,9)

D=\sqrt{(-2--4)^{2}+(9-4)^{2}  } \\D=\sqrt{2^{2} +5^{2} } \\D=\sqrt{29}

Perimeter

P=10+14+2\sqrt{29} \\P=24 +2\sqrt{29} \\P= 24+10.77\\P=34.77

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3 years ago
Given the function f(x) = −2x + 8, find x if f(x) = 14 ...?
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