Ask question

Ask question

All categories

3 years ago

13

PLEASE HELP !!!! ILL GIVE BRAINLIEST !!! 100 POINTS

2 answers:

ale4655 [162]3 years ago

8 0

This is not 100 points.... why are you lying

BartSMP [9]3 years ago

6 0

Answer:

<h2><em><u><</u></em><em><u>1</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u><</u></em><em><u>7</u></em><em><u> </u></em><em><u>,</u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u><</u></em><em><u>2</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u><</u></em><em><u>8</u></em></h2><h3><em><u>or</u></em></h3><h2><em><u><</u></em><em><u>4</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u><</u></em><em><u>6</u></em><em><u> </u></em><em><u>,</u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u><</u></em><em><u>3</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u><</u></em><em><u>5</u></em></h2>

Step-by-step explanation:

<h3><em><u>There</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>totally</u></em><em><u> </u></em><em><u>four</u></em><em><u> </u></em><em><u>pairs</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>alternate</u></em><em><u> </u></em><em><u>angles</u></em><em><u>:</u></em></h3>

<em><u>Alternate</u></em><em><u> </u></em><em><u>interior</u></em><em><u> </u></em><em><u>angles</u></em><em><u>:</u></em><em><u>-</u></em>

<em>Pairs</em><em> </em><em>-</em><em> </em><2 and <8 ; <3 and <5

<em><u>Alternate</u></em><em><u> </u></em><em><u>exterior</u></em><em><u> </u></em><em><u>angles</u></em><em><u>:</u></em><em><u>-</u></em>

<em>Pairs</em><em> </em><em>-</em><em> </em><1 and <7 ; <4 and <6

<h3>{<em><u>You</u></em><em><u> </u></em><em><u>can</u></em><em><u> </u></em><em><u>choose</u></em><em><u> </u></em><em><u>any</u></em><em><u> </u></em><em><u>two</u></em><em><u> </u></em><em><u>pair</u></em><em><u>}</u></em></h3>

You might be interested in

Solve the equation on the interval [0, 2pi): 12cos^2 x-9=0<br><br><br> What to do?

siniylev [52]

Answer:

$\large\boxed{x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}}$

Step-by-step explanation:

$12\cos^2x-9=0\qquad\text{add 9 to both sides}\\\\12\cos^2x=9\qquad\text{divide both sides by 12}\\\\\cos^2x=\dfrac{9}{12}\\\\\cos^2x=\dfrac{9:3}{12:3}\\\\\cos^2x=\dfrac{3}{4}\to\cos x=\pm\sqrt{\dfrac{3}{4}}\\\\\cos x=\pm\dfrac{\sqrt3}{2}\\\\\text{Look at the picture}\\\\x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}$

6 0

3 years ago

The formula for the nth square number is S_n = n^2. Use the formula to find the 11th square number.

Klio2033 [76]

Answer:

121.

Step-by-step explanation:

$S_{11} = 11^{2} = 121.$ So, the 11th square number is 121.

4 0

3 years ago

What's 1.6 rounded to the nearest tenth

dem82 [27]

Are there anymore numbers after the six? If there is not then it si already rounded to the nearest tenth.

7 0

3 years ago

Read 2 more answers

Compare and contrast the radius, and the diameter of a circle. How are they alike? How are they different?

Furkat [3]

You should take into account that the radius is half the diameter and the diameter is the length from the side to side of a circle.

5 0

3 years ago

Simplify the product 7x(x+4)

Alika [10]

=7x2+28x
hope this helps

4 0

3 years ago

Read 2 more answers