FIGURE OUT THE PERIMETER
2 answers:
<em>Answer:</em>
<em>56m</em>
<em>Step-by-step explanation:</em>
<em>Calculate each side's length.</em>
<em>Side A's length: 12m</em>
<em>Side B's length: 16m</em>
<em>Side C's length: 7m</em>
<em>Side D's length: 11m</em>
<em>Side E's length: 5m</em>
<em>Side F's length: 5m</em>
<em>5 + 5 + 7 + 11 + 12 + 16</em>
<em>10 + 7 + 11 + 12 + 16</em>
<em>17 + 11 + 12 + 16</em>
<em>28 + 12 + 16</em>
<em>40 + 16</em>
<em>56</em>
<em>Your answer is 56m.</em>
<em>Hope this helps. Have a nice day.</em>
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Answer:
Step-by-step explanation:
A. y-Intercept of ƒ(x)
ƒ(x) = x² - 4x + 3
f(0) = 0² - 4(0) + 3 = 0 – 0 + 3 = 3
The y-intercept of ƒ(x) is (0, 3).
If g(x) opens downwards and has a maximum at y = 3, it's y-intercept is less than (0, 3).
Statement A is TRUE.
B. y-Intercept of g(x)
Statement B is FALSE.
C. Minimum of ƒ(x)
ƒ(x) = x² - 4x + 3
a = 1; b = -4; c = 3
The vertex form of a parabola is
y = a(x - h)² + k
where (h, k) is the vertex of the parabola.
h = -b/(2a) and k = f(h)
h = -b/2a = -(-4)/(2×1 = 2
k = f(2) = 2² - 4×2 + 3 =4 – 8 +3 = -1
The minimum of ƒ(x) is -1. The minimum of ƒ(x) is at (2, -1).
Statement C is FALSE.
D. Minimum of g(x)
g(x) is a downward-opening parabola. It has no minimum.
Statement D is FALSE