Step-by-step explanation:
work is shown and pictured
Using the distance formula:
Distance = √((x2-x1)^2 + (y2-y1)^2)
Distance = √((5-2)^2 + (-8 - -4)^2
Distance = √(3^2 + -4^2)
Distance = √(9 +16)
Distance = √25
Distance = 5
(8, 5) I think... because that’s what it says on. Khan academy
supplementary angles are 180°
<1+<2=180°
given that <1=112°
112°+<2=180°
<2=180°-112°
<2=68°
Answer:
Cost of a kit is $20
cost of a microscope is $80
Step-by-step explanation:
Here, we want to write a set of equations and solve
Let the cost of a microscope be $m while the cost of a kit be $k
Total cost of 38 microscopes will be 38 * m = $38m
Total cost of 47 kits = 47 * k = $47k
The sum of these is $3980
That will be;
47k + 38m = 3980 ••••••(i)
A microscope cost 4 times a kit
Mathematically;
m = 4k •••••••••(ii)
Substitute ii into i
47k + 38(4k) = 3980
47k + 152k = 3980
199k = 3980
k = 3980/199
k = $20
Recall;
m = 4k
m = 4 * 20 = $80