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salantis [7]
3 years ago
8

QUICK!! TEN POINTS AND BRAINLIEST FOR WHOEVER GETS IT RIGHT!

Mathematics
1 answer:
grigory [225]3 years ago
8 0

Answer:

3 units

I counted the spaces XD lol good luck

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Which of the following sets could not be the lengths of the sides of a triangle?
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The steps for adding integers are the same as for subtracting them. <br><br> True or False?
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3 years ago
Please helpppppppppppp
morpeh [17]

Answer:

7.7 km

Explanation:

Use cosine rule as here given two sides and one angle.

Cosine rule states:

a² = b² + c² - 2bc cos(A)

While solving, treat a = 7.5 km as to that opposite angle is given of 68°

then b = missing side, c = 5.2 km, A = 68°

Applying rule:

7.5² = b² + 5.2² - 2(b)(5.2) cos(68)

56.25 = b² + 27.04 - 3.8959b

56.25 - 27.04 = b² - 3.8959b

b² - 3.8959b = 29.21

b² - 3.8959b - 29.21 = 0

apply quadratic equation, Here [a = 1, b = - 3.8959, c = -29.21]

\sf b = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \quad\:when \:\ ax^2 + bx + c = 0

\sf b = \dfrac{ -(-3.8959) \pm \sqrt{(-3.8959)^2 - 4(1)(-29.21)}}{2(1)}

\sf b = 7.69 291 \quad or \quad b = -3.797

\sf b = 7.7 \quad (rounded \ to \ nearest \ tenth)

As length cannot be negative. Hence the value of b is only 7.7 km

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