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2 years ago

3x-4>11 solve and graph if possible

Mathematics

1 answer:

gavmur [86]2 years ago

4 0

Answer:

3x−4>11

Step 1: Add 4 to both sides.

3x−4+4>11+4

3x>15

Step 2: Divide both sides by 3.

$\frac{3x}{3}$ > $\frac{15}{3}$

x>5

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2 years ago

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777dan777 [17]

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2 years ago

PLEASE HELP ME IM STRUGGLING!!!

Kitty [74]

Answer:

The required answer is $c=7\sqrt{3}$

Therefore the number in green box should be 7.

Step-by-step explanation:

Given:

AB = 7√2

AD = a , BD = b , DC = c , AC = d

∠B = 45°, ∠C = 30°

To Find:

c = ?

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In Right Angle Triangle ABD Sine identity we have

$\sin B = \dfrac{\textrm{side opposite to angle B}}{Hypotenuse}\\$

Substituting the values we get

$\sin 45 = \dfrac{AD}{AB}= \dfrac{a}{7\sqrt{2}}$

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Now in Triangle ADC Tangent identity we have

$\tan C = \dfrac{\textrm{side opposite to angle C}}{\textrm{side adjacent to angle C}}$

Substituting the values we get

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3 years ago

25 — 3x = 40<br> x =<br><br> Please answer quick thanks

Keith_Richards [23]

Answer:

x=-5

Step-by-step explanation:

-3x+25=40. You want to isolate x so you have to subtract 25 from both sides. -3x=15. We then want x to be isolated so we have to divide both sides by -3 to make x by itself. x=-5. Therefore, x=-5.

If this helps please mark as brainliest

4 0

2 years ago

Read 2 more answers