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ZanzabumX [31]
3 years ago
8

CAN ANYONE PLEASE HELP ME !!

Mathematics
1 answer:
Ivan3 years ago
8 0

Answer:

The answer is 9.

Step-by-step explanation:

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Use the figure to answer the qu 8 m 14 m 16 m 132 m 12 m What is the area of figure?​
Nastasia [14]

Answer:

The answer is D. 136

1. find simple shapes like rectangles and square, then find the areas and add them

8 0
4 years ago
If (x-2)(y-1)=3 and (x+2)(2y-5)=15,
daser333 [38]

Answer:

Equation 1, Multiplied by 2: 2x + 4y = 10

Equation 1, Multiplied by 2: 2x + 4y - 10 = 10 - 10

Equation 1, Multiplied by 2: 2x + 4y - 10 = 0

Equation 1, Multiplied by 2: 2x - 2x + 4y - 10 = 0 - 2x

Equation 1, Multiplied by 2: 4y - 10 = - 2x

Equation 1, Multiplied by 2: - 10 + 4y = - 2x

Notice that Equation 1 = Equation 2

One Solution

Equation 1: x - y = -10

Equation 2: 2x + 3y = 15

5 0
3 years ago
Solve the two-step equation. − 2 3 x – 21 4 = 27 4 x =
MissTica

Answer:

x = - 18

Step-by-step explanation:

Add the opposite of the constant on the left:

-2/3x = 21/4 +27/4 = 48/4 = 12

Multiply the equation by the inverse of the coefficient of x:

x = (-3/2)(12) = -18

The solution is x = - 18

5 0
3 years ago
Read 2 more answers
I HAVE 1 HUNDREDS, 9 TENS, 9 ONES, 8 TENTHS AND 1 HUNDRETHS.WHAT NUMBER AM I?
myrzilka [38]
199.81 is the answer
3 0
4 years ago
A survey of 85 families showed that 36 owned at least one DVD player. Find the 99% confidence interval estimate of the true prop
attashe74 [19]

Answer:

0.424 - 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.286

0.424 + 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.562

The 99% confidence interval would be given by (0.286;0.562)

Step-by-step explanation:

Information given:

X= 36 represent the families owned at least one DVD player

n= 85 represent the total number of families

\hat p=\frac{36}{85}= 0.424 represent the estimated proportion of families owned at least one DVD player

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.05. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.424 - 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.286

0.424 + 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.562

The 99% confidence interval would be given by (0.286;0.562)

8 0
3 years ago
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