So for this problem, the x-axis is the horizontal line in the center.
Go to where -2 is on the x-axis as shown. Use your finger to trace along since that's usually helpful in finding the point.
Move your finger from -2 on the x-axis to where the solid black line is. On the right side of that, you can see that the y-axis holds the number 2 which is what the y equals for this solid line.
Therefore, the answer should be c.) y = 2
Answer:
(a) 3.75
(b) 2.00083
(c) 0.4898
Step-by-step explanation:
It is provided that X has a continuous uniform distribution over the interval [1.3, 6.2].
(a)
Compute the mean of X as follows:
(b)
Compute the variance of X as follows:
(c)
Compute the value of P(X < 3.7) as follows:
![P(X < 3.7)=\int\limits^{3.7}_{1.3}{\frac{1}{6.2-1.3}}\, dx\\\\=\frac{1}{4.9}\times [x]^{3.7}_{1.3}\\\\=\frac{3.7-1.3}{4.9}\\\\\approx 0.4898](https://tex.z-dn.net/?f=P%28X%20%3C%203.7%29%3D%5Cint%5Climits%5E%7B3.7%7D_%7B1.3%7D%7B%5Cfrac%7B1%7D%7B6.2-1.3%7D%7D%5C%2C%20dx%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B4.9%7D%5Ctimes%20%5Bx%5D%5E%7B3.7%7D_%7B1.3%7D%5C%5C%5C%5C%3D%5Cfrac%7B3.7-1.3%7D%7B4.9%7D%5C%5C%5C%5C%5Capprox%200.4898)
Thus, the value of P(X < 3.7) is 0.4898.
Well if there are 3 outcomes just add the two other outcomes and subtract from 1
so 0.4+0.25=0.35
so the third outcomes has a 0.35 chance of happening or 35%
Answer:
I cannot not give the correct solution, need more context. How many children are there, how many adults are in the family? So I will explain in my explanation.
Step-by-step explanation:
If more context were given, for example:<em> 2 adults and 2 children.</em>
Then the bakers would have bought 2 adult tickets for ___ each
Then the bakers would have bought 3 children's tickets for ___ each
So using what we know we can create an equation:
<em>2A+3C=28</em>,<em> </em>
meaning 2 adult tickets plus 3 children's tickets costs a total of $28.
So we divide 28 by 5, which is the total amount of tickets.
28/5=5.6
So to figure the cost of children's tickets multiply the cost by amount.
3*$5.6=$16.8, C=16.8
To figure out the cost of the adults tickets multiple the cost by the amount.
2*$5.6=$11.2, A=11.2
a) the bakers would have bought <u>2</u> adult tickets for <u>5.6</u> each.
b) the bakers would have bought <u>3</u> children's tickets for <u>5.6</u> each.
x = 1
5(1)= -4y + 4
5= -4y + 4
-4. -4 1 = -4y
y = -¼
x = 2...
10 = -4y + 4 6 = -4y y = -3/2
x = 3..
15 = -4y + 4 11 = -4y y = -11/4
