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nikklg [1K]
3 years ago
14

Trig. help. How does

29%20%3D%20sinx" id="TexFormula1" title="2sin (\frac{1}{2} x)cos( \frac{1}{2} x) = sinx" alt="2sin (\frac{1}{2} x)cos( \frac{1}{2} x) = sinx" align="absmiddle" class="latex-formula"> ?
Mathematics
1 answer:
kotegsom [21]3 years ago
5 0
Recall that 2sin(x) cos(x) is actually equal to sin(2x).

We can prove this by expanding sin(2x) to sin(x + x).
sin(x + x) = sin(x) cos(x) + cos(x) sin(x) = 2sinxcosx

Thus, 2sin(x/2)cos(x/2) can be rewritten in the form:
sin(2x/2), and this simplifies down to sinx.
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What is the answer??
Lemur [1.5K]

Answer:

h(3) = - 140

Step-by-step explanation:

Generate the terms in the sequence by substituting n = 2 and 3 into h(n)

h(2) = h(2 - 1) × 2 = h(1) × 2 = - 35 × 2 = - 70

h(3) = h(3 - 1) × 2 = h(2) × 2 = - 70 × 2 = - 140

8 0
3 years ago
An ice cream factory makes 350 quarts of ice cream in 2 hours. How many quarts could be made in 36 hours? What was that rate per
lapo4ka [179]

Answer:

36 hours - 6,300

24 hours - 4,200

8 0
3 years ago
If you were to add 5 to my number and then divide by 4, you would get 7
Norma-Jean [14]
Let's make an equation. T will be the number.
(T+5)/4=7
Let's multiply both sides by 4 to get T by itself.
T+5=28
Subtract 5 from both sides.
T=23
Your number is 23.
3 0
3 years ago
Read 2 more answers
PLEASE HELP! WILL MARK BRAINLIEST!! :D
netineya [11]

Hope this helps

Given a term in a geometric sequence and the common ratio find the first five terms, the explicit formula, and the recursive formula. Given two terms in a geometric sequence find the 8th term and the recursive formula. Determine if the sequence is geometric. If it is, find the common ratio.

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3 years ago
I only need help with number 7
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a,c,d are all correct

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3 years ago
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