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Papessa [141]
3 years ago
9

In ΔFGH, the measure of ∠H=90°, FH = 39, GF = 89, and HG = 80. What ratio represents the cotangent of ∠G?

Mathematics
1 answer:
hoa [83]3 years ago
6 0

Given:

In ΔFGH, the measure of ∠H=90°, FH = 39, GF = 89, and HG = 80.

To find:

The ratio which represents the cotangent of ∠G.

Solution:

In a right angle triangle, the ratio of the cotangent of an angle is

\cot \theta =\dfrac{Base}{Perpendicular}

It is also written as

\cot \theta =\dfrac{Adjacent}{Opposite}

In ΔFGH, the measure of ∠H=90°. So,

\cot G =\dfrac{HG}{FH}

\cot G =\dfrac{80}{39}

Therefore, the ratio for the cotangent of ∠G is \cot G=\dfrac{80}{39}.

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Step-by-step explanation:

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Answer:

See explanation below

Step-by-step explanation:

<u>First we will solve the radical equation</u> (which I guess was problem 1),

Let's start by simplifying it:

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Now we will solve the equation by squaring both sides of the equation:

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This happens because <u>when we first squared both sides of the equation in the first part of the problem we missed one value for x </u>(remember that all roots have 2 answers, a positive one and a negative one) while squares are always positive.

When we squared the root, we missed one value for x and that is why the calculation does not produce a solution to the equation.

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Answer:

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Step-by-step explanation:

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The answer is d x 15 =100

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