Given:
In ΔFGH, the measure of ∠H=90°, FH = 39, GF = 89, and HG = 80.
To find:
The ratio which represents the cotangent of ∠G.
Solution:
In a right angle triangle, the ratio of the cotangent of an angle is

It is also written as

In ΔFGH, the measure of ∠H=90°. So,


Therefore, the ratio for the cotangent of ∠G is
.