Since (5/31)/(15/23)=(5/31)*(23/15) (by finding the reciprocal and multiplying), we get 115/465. Since they are both divisible by 5, we learn that 5 goes into 115 23 times and into 465 93 times (since 465/5=93), resulting in 23/93. Since 23 is a prime number (their only factors are 23 and 1), we end there
Y=-9+6
y=-3
The answer is B
1.) <span>It typically takes teachers 9 minutes longer than students to get ready for school. - The median of two data = Teachers 25 - Students 16: typically, teachers take 25 mins to get ready and students take 16 mins to get ready.
2.) </span><span>Both of the means are correct, but the reasoning is incorrect. - the mean absolute deviation for team A is 2 and for team B is 0.8. Greater mean does not signify higher mean absolute deviation.
3.) </span><span>The students tend to have fewer siblings than the teachers. - the teachers have a wide range of data and they have more siblings than the students so the first choice is the better option.
4.) </span><span>between 120 and 153 mph in race A; between 125 and 145 mph in race B - get the data from the lower whisker till the median.</span>
Answer:
A = 45 units^2
Step-by-step explanation:
This is a trapezoid
A = 1/2 (b1+b2) h
b1 is the top = 7
b2 is the bottom = 11
h = 5
A = 1/2 ( 7+11) *5
A = 1/2 ( 18)*5
A = 45 units^2
