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Gnoma [55]
3 years ago
12

If u know lmk pls and ty

Mathematics
1 answer:
statuscvo [17]3 years ago
3 0

Answer:

  • A) The cat weights 7 kilograms when it is 4 months old.

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hope it helps...

have a great day

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Answer:

6

Step-by-step explanation:

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E. What was the population in 1995? (the initial population for this situation) *
MaRussiya [10]

Answer:

Part e) 501,170\ people

Part f) The decay factor is 0.98

Part g) Decreasing

Part h) y=25,400(1+0.11)^x

Part i) 345,071\ people

Step-by-step explanation:

we have

f(x)=501,170(0.98)^x

where

x ----> is the number of years since 1995

f(x) ----> is the population of a Texas city

Part e) What was the population in 1995?

we know that

The equation of a exponential function decay is of the form

y=a(1-r)^x

where

a represent the initial value (y-intercept of the function)

therefore

In the given function

The initial value is the value of the function when the value of x is equal to zero

so

For x=0

f(x)=501,170(0.98)^0=501,170\ people

Part f) What is the growth/decay factor?

we know that

The equation of a exponential decay function is of the form

y=a(1-r)^x

where

(1-r) ----> is the decay factor

In this problem we have

f(x)=501,170(0.98)^x

(1-r)=0.98

therefore

The decay factor is 0.98

Part g) Is the population increasing or decreasing?

we know that

If the factor is greater than 1 then the population is increasing

If the factor is less than 1 and greater than zero, then the population is decreasing

In this problem

the factor is less than 1

0.98< 1 ----> is a decay factor

therefore

The population is decreasing

In the year 1995, the population of a town in Texas was recorded as 25,400 people. Each year since 1995, the population has increased on average by 11% each year

Part h) Write an exponential function to represent the town's population, y, based on the number of years that pass, x after 1995

we know that

The equation of a exponential growth function is of the form

y=a(1+r)^x

we have

a=25,400\\r=11\%=11/100=0.11

substitute

y=25,400(1+0.11)^x

y=25,400(1.11)^x

Part i) Based on the function, what is the population predicted to be in the year 2020?

Remember that the number of years is since 1995

so

x=2020-1995=25 years

substitute the value of x in the exponential function

y=25,400(1.11)^25=345,071\ people

3 0
4 years ago
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Answer:

he went 0.2km south

Step-by-step explanation:

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Step-by-step explanation:

<u>Step 1:  Distribute</u>

3(4x - 2) = 9 + 2x + 5

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<u>Step 3:  Subtract 2x from both sides</u>

12x - 2x = 20 + 2x - 2x

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