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3 years ago

Which function is nonlinear?

Mathematics

1 answer:

lutik1710 [3]3 years ago

4 0

Answer:

(-1,5), (0,4) ,(1,3) ,(3,1) is linear so dont pick it

(-4,-7), (-2,-6), (2,-4), (4,-3) is linear

you know what I'll just say it wait a minute is there like a other option

Step-by-step explanation:

U can tell by graphing them out yourself and if u see a straight line then it linear, and if you see a curved loop then it's non- linear. but I'll do it :)

You might be interested in

How much money should be invested in an account that earns 8% interest compounded quarterly to yield $10,000 in 4 years? (Round

sweet [91]

Answer:

757,576cents

Step-by-step explanation:

Given

Amount = $10000

Time = 4years

Rate = 8%

n = 1/4 year (compounded quarterly

Using the formula to get the principal

A = P(1+r/n)^nt

10000 = P(1+0.08/0.25)^4(1/4)

10000 = P(1+0.32)

10000= 1.32P

P = 10000/1.32

P = 7575.76

Hence he suppose to invest $7575.76 which is equivalent to 7575.76×100 cents i.e 757,576cents

4 0

3 years ago

MARKING BRAINIEST Can you help me with this math problem please ?

mihalych1998 [28]

Answer:

You answer can be written for Solving X two different ways

The inquitly form is

x $\geq$ -6

Interval Notation is

{-6,∞)

Step-by-step explanation:

In order to graph put a close dot on the number -6 and then color your line to the right of the number line. Because the infinity sign is positive so all the number after the -6 is positive. So a close dot on the number -6 and then draw a line or color a line to the right of the number line

6 0

3 years ago

The two-way table shows the number of men and women who voted for Candidate A or B.

Doss [256]

We're looking for a percentage of the people who voted for Candidate-A. So
the first thing we need to know is: How many people voted for Candidate-A ?

The number of people who voted for Candidate-A is

(1,253 men) + (1,921 women) = 3,174 people .

The question is: What percent of those people were women ?

Out of the total, 1,921 were women.
To find percent, you divide the part by the total.

1,921 / 3,174 = 0.6052 .

Changed to percent and rounded to the nearest whole one, that's 61% .

6 0

3 years ago

Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive

LenaWriter [7]

Answer:

(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.

(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.

(d) The probability that at most 1 of the next three vehicles passes is 0.216.

(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

Step-by-step explanation:

Let X = number of vehicles that pass the inspection.

The probability of the random variable X is P (X) = 0.70.

(a)

Compute the probability that all the next three vehicles inspected pass the inspection as follows:

P (All 3 vehicles pass) = [P (X)]³

$=(0.70)^{3}\\=0.343$

Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.

(b)

Compute the probability that at least 1 of the next three vehicles inspected fail as follows:

P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)

$=1-0.343\\=0.657$

Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c)

Compute the probability that exactly 1 of the next three vehicles passes as follows:

P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)

= P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)

+ P (Only 3rd vehicle passes)

$=(0.70\times0.30\times0.30) + (0.30\times0.70\times0.30)+(0.30\times0.30\times0.70)\\=0.189$

Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.

(d)

Compute the probability that at most 1 of the next three vehicles passes as follows:

P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)

+ P (0 vehicles passes)

$=0.189+(0.30\times0.30\times0.30)\\=0.216$

Thus, the probability that at most 1 of the next three vehicles passes is 0.216.

(e)

Let X = all 3 vehicle passes and Y = at least 1 vehicle passes.

Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:

$P(X|Y)=\frac{P(X\cap Y)}{P(Y)} =\frac{P(X)}{P(Y)} =\frac{(0.70)^{3}}{[1-(0.30)^{3}]} =0.3525$

Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

7 0

3 years ago

Ken watches a marching band. He sees 2 rows of flute players. Six people are in each row. He sees 8 trombone players. How many f

sukhopar [10]

Twelve flute players.

Eight trombone players.

20 total of flute and trombone players.

6 0

4 years ago