Answer:
The amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.
Step-by-step explanation:
Let the random variable <em>X</em> represent the amount of money that the family has invested in different real estate properties.
The random variable <em>X</em> follows a Normal distribution with parameters <em>μ</em> = $225,000 and <em>σ</em> = $50,000.
It is provided that the family has invested in <em>n</em> = 10 different real estate properties.
Then the mean and standard deviation of amount of money that the family has invested in these 10 different real estate properties is:

Now the lowest 80% of the amount invested can be represented as follows:

The value of <em>z</em> is 0.84.
*Use a <em>z</em>-table.
Compute the value of the mean amount invested as follows:


Thus, the amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.
Answer:
7.25cm
Step-by-step explanation:
Let the complete question be;
<em>Jill cuts a piece of cardboard in the shape of a trapezoid. The area of the is 43.5sp cm. If bases are 3.5cm and 8.5cm long, what is the height.</em>
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Area of a trapezoid = 1/2(a+b)*h
a and b are the parallel sides (bases)
h is the height
Given
a = 3.5cm
b = 8.5cm
A = 43.5 sq.cm
Required
Height h
Substitute the given values into the expression
Area of a trapezoid = 1/2(a+b)*h
43.5 = 1/2(3.5+8.5)*h
43.5 = 1/2 * 12h
43.5 = 6h
h = 43.5/6
h = 7.25cm
Hence the height is 7.25cm