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2 answers:
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The roof will be in the shape of an isosceles triangle with a base length of 30 m and two sides that are 17 m. The two 17 m beams will have the same angle of elevation since they have to might in the middle.
So to find the angle of elevation, we can split the roof in half vertically to create a right triangle. The base will now be 15 m, and the hypotenuse will be 17. Now we can use a trigonometry function to solve for the angle. We know the hypotenuse and the side adjacent to the angle, so we can use cosine.
The answer is 28.1 degrees
So to find the angle of elevation, we can split the roof in half vertically to create a right triangle. The base will now be 15 m, and the hypotenuse will be 17. Now we can use a trigonometry function to solve for the angle. We know the hypotenuse and the side adjacent to the angle, so we can use cosine.
The answer is 28.1 degrees
Answer:
<em>m∠C = 30° </em>
Step-by-step explanation:
If ΔADB is an equilateral, then m∠A = m∠ADB = m∠DBA = 60°
If ΔDBC isosceles with DB ≅ BC, then m∠C = m∠BDC ;
m∠C + m∠BDC = m∠DBA = 60° ⇒ <em>m∠C = 30°</em>
