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faust18 [17]
3 years ago
14

Find the length of the arc to 2 decimals places

Mathematics
1 answer:
HACTEHA [7]3 years ago
7 0

Answer:

Step-by-step explanation:

The formula for arc length is

AL=\frac{\theta}{360}*2\pi r where theta is the measure of the central angle and r is the radius. We have both of those pieces of info; filling in:

AL=\frac{30}{360}*2(3.14) (4) and simplifying a bit:

AL=\frac{1}{12}(8)(3.14) and a bit more:

AL=\frac{25.12}{12} and finally, to

AL = 2.09 m

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2-13^3-10(23+21) = X
Tanya [424]

Answer:

x= -2635

Step-by-step explanation:

2 - 2197 - 10 x 44 = x

2- 2197 - 440 = x

-2635 = x

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3 years ago
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What is the sum of the solutions to (x − 6)(x + 0.7) = 0 ?
Nonamiya [84]

Answer:

5.3

Step-by-step explanation:

(x − 6)(x + 0.7) = 0

using the zero product property

x-6=0   x+.7 =0

x-6+6 = 0+6       x+.7 -.7 = 0-.7

x = 6                   x= -.7

sum of the solutions

6+-.7 = 5.3

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3 years ago
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The wave rly brush company issued 4,000 shares of common stock worth 200,000.00 total. What is the par value of each share
vivado [14]

I believe the answer is 50,000, I could be wrong.

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3 years ago
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What is the answer for question 1 and how
quester [9]

Step-by-step explanation:

ABC is an isoceles triangle (both legs are equally long). and AB is its baseline.

OC is now a median for ABC splitting the angle at C and AB in half.

so, we have 2 right-angled triangles : OAC and OBC.

the half-angles at C are 42/2 = 21°.

the angles at A and B are 90°.

and the half-angles at O are 180 - 90 - 21 = 69°.

remember that the sum of all angles in a triangle must always be 180°.

AB are the heights of both of these triangles.

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4 0
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Sheldon harvest the strawberries and tomatoes in his garden. He picks 1 2/5 kg lesss strawberries in the morning tha in the afte
Tpy6a [65]

Answer:

3\frac{13}{20}=3.65 kg.

Step-by-step explanation:        

Let S be amount of strawberries picked in the afternoon.

We have been given that Sheldon harvest the strawberries and tomatoes in his garden. He picks 1 2/5 kg less strawberries in the morning than in the afternoon and the strawberries picked in morning are 2\frac{1}{4} kg.

To find the amount of strawberries picked by Sheldon in the afternoon we will add 2\frac{1}{4} and 1\frac{2}{5}  :

S= 2\frac{1}{4}+1\frac{2}{5}      

Upon converting our given mixed fractions into improper fraction we will get,

S= \frac{9}{4}+\frac{7}{5}

Now let us have a common denominator.

S=\frac{9*5}{4*5}+\frac{7*4}{5*4}

S=\frac{45}{20}+\frac{28}{20}

S=\frac{45+28}{20}

S=\frac{73}{20}  

S=3\frac{13}{20}  

S=3.65

Therefore, Sheldon picked 3\frac{13}{20}=3.65 kg of strawberries in the afternoon.  

3 0
3 years ago
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