3 years ago

3.5.57

Mathematics

1 answer:

grin007 [14]3 years ago

8 0

Answer:

y=4x+23 (lmk if you need me to explain)

Step-by-step explanation:

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Mrrafil [7]

Answer: hay well it is relly hard to read can you take a better photo hun

Step-by-step explanation:

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2 years ago

Question number 8. Prove that 3 + √5 is an irrational number.

Marina86 [1]

Answer :

Let's assume the opposite of the statement i.e., 3 + √5 is a rational number.

$\\ \sf \: 3 + \sqrt{5} = \frac{a}{b} \\ \\ \qquad \: \tiny \sf{(where \: \: a \: \: and \: \: b \: \: are \: \: integers \: \: and \: \: b \: \neq \: 0)} \\$

$\\ \sf \: \sqrt{5} = \frac{a}{b} - 3 = \frac{a - 3b}{b} \\$

Since, a, b and 3 are integers. So,

$\\ \sf \: \frac{p - 3b}{b} \\ \\ \qquad \tiny \sf{ \: (is \: \: a \: \: rational \: \: number \:) } \\$

Here, it contradicts that √5 is an irrational number.

because of the wrong assumption that 3 + √5 is a rational number.

$\\$

Hence, 3 + √5 is an irrational number.

7 0

3 years ago

Solve for x in the equation x²-12x+59=0

lyudmila [28]

${x}^{2} - 12x + 59 = 0 \\ {x}^{2} - 12x + 36 + 23 = 0 \\ {x}^{2} - 12x + 36 = - 23 \\ {(x - 6)}^{2} = - 23 \\ x - 6 = + - \sqrt{ - 23} = + - i \sqrt{23} \\ x = 6 + - i \sqrt{23}$