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Studentka2010 [4]
2 years ago
5

What's the range in the question below. Please answer one of the answer choices.

Mathematics
1 answer:
lubasha [3.4K]2 years ago
3 0

Answer:

yo I'm doing the same thing

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Molodets [167]

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b

Step-by-step explanation:

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3 years ago
2^x+5 = 3^1-x use logarithms to solve the exponential equation. round answer to 3 decimal places.
marysya [2.9K]
2^{x+5}=3^{1-x}\ \ \ \ \ /log_2()\\\\log_22^{x+5}=log_23^{1-x}\\\\x+5=(1-x)log_23\\\\x+5=log_23-xlog_23\\\\x+xlog_23=log_23-5\\\\x(1+log_23)=log_23-5\ \ \ \ /:(1+log_23)

x=\frac{log_23-5}{1+log_23}\\-------------\\log_23\approx1.5849625\\----------------\\x\approx\frac{1.5849625-5}{1+1.5849625}\approx-1.321
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3 years ago
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gulaghasi [49]

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1/9

Step-by-step explanation:

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viva [34]

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1/2 or 0.5

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