The point equidistant from a(2, -2) and b(-4, 6) is the midpoint
For (x₁, y₁) and (x₂, y₂) the midpoint is given by:
( (x₁ + x₂)/2 , (y₁ + y₂)/2 )
Midpoint = ( (2 + -4)/2 , (-2 + 6)/2 )
= ( (2 - 4)/2 , (6 - 2)/2) ) = ( -2/2, 4/2) = (-1, 2)
So the point equidistant from the two points is (-1, 2).
Answer:
u will have $309000 at the end of the year
Step-by-step explanation:
1year=12month
25,750x12=309000
Answer= 87
You need to square root 60^2 + 63^2
Answer:
d
Step-by-step explanation:
=1000
10^3 is 1000
We can prove this by doing a statement and reason (more or less). The first thing we need to do is a construction of segment OG which is parallel to BC and touches A. Since it forms a straight line, we can say that m<OAB + m<A + m<GAC is equal to 180° (because it is a straight line). But, by alternate interior angles theorem, we can say that m<B = m<OAB and m<C = m<GAC. Therefore, by transitivity, m<A + m<B + m<C = 180°. Since angles A, B, and C are the interior angles of triangle ABC, we proved that the sum of the interior angles of ABC is 180°.
