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Vesnalui [34]
2 years ago
13

Please help i don’t understand

Mathematics
1 answer:
choli [55]2 years ago
6 0

Is that everything for the problem??

||-//

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PLEASE HELP ANSWER BOTH PARTS!!! DUE SOON
soldi70 [24.7K]

Answer:

c. 69

b. 7

Step-by-step explanation:

4 0
1 year ago
You roll a number cube twice. Find the probability of the events. Rolling an odd number 2 or a 4.
forsale [732]

Answer: see below

Step-by-step explanation:

If this is a 6 sided die then the only possible roll that isnt an odd, a 2, or a 4 is 6.

The probability of something happening is also the probability of something not happening. So in order to not roll an odd, a 2 or a 4 in two rolls, you have to roll a 6 twice.

P = 1 - (1/6)(1/6) = 1 - (1/36) = (35/36)

5 0
3 years ago
Use the formula to determine the area of squares with side lengths of 3 cm, 10.5 cm, and π cm.
Nataliya [291]

Answer:

For length of side = 3 cm

Area of the square = 9 cm²

For length of side = 10.5 cm

Area of the square =  110.25 cm²

For length of side = π cm

Area of the square = 9.869 cm²

Step-by-step explanation:

The area of a square is given as :

Area = Side²

therefore,

For length of side = 3 cm

Area of the square = ( 3 cm )² = ( 3 × 3 ) cm² = 9 cm²

For length of side = 10.5 cm

Area of the square = ( 10.5 cm )² = ( 10.5 × 10.5 ) cm² = 110.25 cm²

For length of side = π cm

Area of the square = ( π cm )²  

= ( π × π ) cm²                

= 3.14² cm²                                [π = 3.14]

= 9.869 cm²

8 0
3 years ago
Help with this please!!
kompoz [17]

Answer:

Positive hope it help :D

Step-by-step explanation:

Sorry if I’m not right :/

6 0
2 years ago
Which theorem or postulate proves that △ABC and △DEF are similar?
yan [13]

Answer:

△ABC and △DEF are similar by SAS Similarity Theorem.

Option (C) is correct .

Step-by-step explanation:

Definition of SAS Similarity property

Two triangles are said to be similar by SAS Similarity property If two sides are proportional and one corresponding angle congruent .

In △ABC and △DEF

\frac{ED}{AB}= \frac{7}{21}

\frac{ED}{AB}= \frac{1}{3}

and

\frac{EF}{BC}= \frac{11}{33}

\frac{EF}{BC}= \frac{1}{3}

Thus

\frac{ED}{AB}=\frac{EF}{BC}= \frac{1}{3}

∠ABC = ∠DEF  (As given in the figure )

Thus △ABC and △DEF are similar by SAS Similarity property .

7 0
2 years ago
Read 2 more answers
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