Answer:
The 99% confidence interval for the mean loss in value per home is between $5359 and $13463
Step-by-step explanation:
We are in posession of the sample's standard deviation, so we use the student's t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 45 - 1 = 44
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 44 degrees of freedom(y-axis) and a confidence level of ![1 - \frac{1 - 0.99}{2} = 0.995([tex]t_{995}](https://tex.z-dn.net/?f=1%20-%20%5Cfrac%7B1%20-%200.99%7D%7B2%7D%20%3D%200.995%28%5Btex%5Dt_%7B995%7D)
). So we have T = 2.6923
The margin of error is:
M = T*s = 1505*2.6923 = 4052.
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 9411 - 4052 = $5359
The upper end of the interval is the sample mean added to M. So it is 9411 + 4052 = $13463
The 99% confidence interval for the mean loss in value per home is between $5359 and $13463
The situation can be modeled as a linear equation:
y = 12x
Where
y: amount of dollars.
x: hours worked.
Independent variable: x (hours worked).
Dependent variable: y (amount of dollars).
he works at most 40 hours per week
Domain: x belongs [0, 40]
To determine the range, we must calculate how much Bill earns per week
y = 12 * (40) = 480.
Range: y belongs [0, 480]
answer
Independent variable: x (hours worked).
Dependent variable: y (amount of dollars.
Domain: x belongs [0, 40]
Range: y belongs [0, 480]
1000 is the missing exponent
These are the answers for your problem
1. 11/2
2. -1/2
3. -17/20
Answer:
For #6, it is 81 degrees, and for #8, it is 100 degrees.
Step-by-step explanation:
For #6, it is on the opposite side, so 81 degrees
For #8, it is also on the opposite side, so 100 degrees
Whenever there are parallel lines going horizontally, the angles measure the same on opposite sides, and to find the measure of an angle next to another angle, subtract it from 180.
