95% C.I. = mean + or - 1.96(standard deviation / sqrt(sample size))
95% C.I. = 57 + or - 1.96(3.5/sqrt(40) = 57 + or - 1.085 = 57 - 1.085 to 57 + 1.085 = 55.92 to 58.09
Therefore, 95% of the mean will occur in the interval 55.92 to 58.09
4 ft because if there all doubled it means there all two and area is length times width so 2 times 2 is 4
Answer:
n = 59
Step-by-step explanation:
I find it easiest to work problems of this kind using a graphing calculator. That way, extraneous solutions can be avoided. It seems to work well to rewrite the problem, so you're looking for a value of n that makes the result zero. Here, that would mean you want ...
... f(n) = √(n+5) -√(n-10) -1
_____
The solution by hand involves eliminating the root symbols. You do that by squaring the equation:
... n +5 -2√((n+5)(n-10)) + n -10 = 1
Now, we isolate the remaining root and square again.
... 2n -6 = 2√((n+5)(n-10)) . . . collect terms, add 2√( ) -1
... n -3 = √(n²-5n-50) . . . . . . . divide by 2
... n² -6n +9 = n² -5n -50 . . . . square both sides
... 59 = n . . . . . . . . . . . . . . . . . add 50 +6n -n²
A quadratic equation has the general form
of: <span>
y=ax² + bx + c
It can be converted to the vertex form in order
to determine the vertex of the parabola. It has the standard form of:
y = a(x+h)² - k
This can be done by completing a square. The steps are as follows:
</span><span>y = 3x2 + 9x – 18
</span>y = 3(x2 <span>+ 3x) – 18
</span>y + 27/4= 3(x2 <span>+ 3x+ 9/4) – 18
</span>y = 3(x2 + 3/2)^2 – 99<span>/4
</span>
Therefore, the first step is to group terms with the variable x and factoring out the coefficient of x^2.