1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Fofino [41]
3 years ago
13

Solve your equation using trail and improvement. A number plus ten times its square root is is equal to one thousand

Mathematics
1 answer:
Alex3 years ago
5 0

Answer:

x \approx 729

Step-by-step explanation:

Given

Let the number be x

So:

x + 10\sqrt x = 1000

Required

Using trial and improvement, find x

This implies that we keep guessing the values of x until we get a value that match the equation.

Let

x = 625

So, we have:

x + 10\sqrt x = 1000

625 + 10 *\sqrt{625}

Take the square root of 625

625 + 10 *\sqrt{625} = 625 + 10 *25

625 + 10 *\sqrt{625} = 625 + 250

625 + 10 *\sqrt{625} = 875

Let

x = 729

So, we have:

x + 10\sqrt x = 1000

729 + 10 * \sqrt{729}

Take the square root of 729

729 + 10 * \sqrt{729} = 729 + 10 * 27

729 + 10 * \sqrt{729} = 729 + 270

729 + 10 * \sqrt{729} = 999

At this point, we can conclude that x is approximately 729 because

999 \approx 1000

So:

x \approx 729

You might be interested in
Find the perimeter of the shaded region below.
Dmitriy789 [7]

9514 1404 393

Answer:

  24x

Step-by-step explanation:

The total length of all vertical segments is 5x·2 = 10x.

The total length of all horizontal segments is (3x+4x)·2 = 14x.

Then the total length of all perimeter segments is ...

  10x +14x = 24x . . . . perimeter of the figure

5 0
3 years ago
A circle has a radius of \sqrt{13}√ ​13 ​ ​​ square root of, 13, end square root units and is centered at (-9.3,4.1)(−9.3,4.1)le
timofeeve [1]

Answer:  The equation of the circle is

x^2+y^2+18.6x-8.2y+90.3=0.

Step-by-step explanation:  We are given to write the equation of the circle with radius √13 units and center at the point (-9.3, 4.1).

We know that

the standard equation of a circle with radius r units and center at the point (h, k) is given by

(x-h)^2+(y-k)^2=r^2.

In the given circle,

radius, r = √13 units  and  center, (h, k) = (-9.3, 4.1).

Therefore, the equation of the circle will be

(x-(-9.3))^2+(y-4.1)^2=(\sqrt{13})^2\\\\\Rightarrow (x+9.3)^2+(y-4.1)^2=13\\\\\Rightarrow x^2+18.6y+86.49+y^2-8.2y+16.81=13\\\\\Rightarrow x^2+y^2+18.6x-8.2y+103.3=13\\\\\Rightarrow x^2+y^2+18.6x-8.2y+90.3=0.

Thus, the equation of the circle is

x^2+y^2+18.6x-8.2y+90.3=0.

7 0
3 years ago
Which of the following ratios is equivalent to 7:9?
rewona [7]

Answer: 28:36

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Find the sum.<br> 5+ (-7)
vazorg [7]

Answer:

-2

Step-by-step explanation:

5 + (-7)

5 - 7

-2

Please let me know if something's wrong!

5 0
3 years ago
What is 4 1/3-(-2/3)
Delicious77 [7]

Answer:

It is 5

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Other questions:
  • Find the value of q in the following system so that the solution to the system is(4,2) 3x-2y=8
    13·1 answer
  • 27 divided by 10 r<br> Equals?
    8·2 answers
  • Help me with this question I’m confused
    6·1 answer
  • C is the midpoint of AE. B is the midpoint of Ac. D is the midpoint of CE
    12·1 answer
  • ZX and zy or supplementary angles. zy measures 49 degrees what is the measure of ZX
    12·1 answer
  • The Burj Khalifa in Dubai is the tallest building in the world, at 2,717 feet. It is 217 feet taller than 5 times the height tha
    8·1 answer
  • What is the slope of the line passing through the point 2 comma negative 1 and the origin?
    14·1 answer
  • The graph of quadratic function is shown on the grid.
    6·1 answer
  • James did an experiment. He started out with 640 bacteria cells. He found that the growth rate of the bacteria
    9·2 answers
  • WRITE AN EQUATION AND SOLVE FOR X.<br> x + 10 -<br> A<br> B<br> С<br> 5<br> 2x+6
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!