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Nitella [24]
3 years ago
9

2) pplllllss hellppp

Mathematics
1 answer:
Dovator [93]3 years ago
6 0

Answer:

A. -1 and 1/3

Step-by-step explanation:

The number -1 and 1/3 is directly to the right of -1 and 2/3 because there is a -1/3 difference between them

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The enrollment at a community college this year is 115% of last year’s enrollment. If there were 1,240 students enrolled at the
wlad13 [49]

Answer:

Multiply 1240 by 1.15 to get 1426 students enrolled this year.

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5 0
3 years ago
How many triangles can be constructed with side lengths of 7.2 cm, 6.9 cm, and 12.8 cm?
Alika [10]

Answer:

One triangle

Step-by-step explanation:

-The triangle's dimensions are defined and fixed.

-Given the fixed dimensions, only one unique triangle can be constructed.

-Hence, only one triangle of the dimensions 7.2cm, 6.9cm and 12.8 cm can be formed.

5 0
3 years ago
Greg bought four roses for $12.80 if the cost per rose is constant how much would 9 roses cost
frozen [14]

Answer:

1.4222222222

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the area of the rectangle.<br> 36<br> kilometers<br> (x-3) kilometers
Vika [28.1K]

Answer:

36x - 108 kilometers²

Step-by-step explanation:

Area = length x width

36 ( x - 3 ) =

36x - 108

-Chetan K

3 0
3 years ago
Calculate the resistance of a 270-cm length of copper wire with a 0.030-cm2 cross-sectional area. ( = 1.8 · 10-6 ohm-cm) R = ___
devlian [24]

Answer:

Given:-

The length of copper wire (L) = 270 cm

Area of cross-sectional (A) = 0.030 cm^2

and specific resistance (ρ) = 1.8 \times 10^{-6} ohm-cm.

Use the formula  R=(Specific resistance*L)/A, to calculate the Resistance(R)

then, R=\frac{1.8 \times 10^{-6} \times 270}{0.030} ohm

Simplify:

R = 0.0162 ohm = 1.62\times 10^{-2} ohm

Therefore, the resistance of copper wire is,  1.62\times 10^{-2} Ω


8 0
3 years ago
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