1st let's calculate the decreasing rate & let V₁ be the initial value & V₂ the final's
we know that V₂=V₁.e^(r,t) where r=rate & t-time (& e=2.718)
After t= 2 years we can write the following formula
2350,000=240,000.e^(2r)==> 235,000/240000 = e^(2r) =>47/48=e^(2r)
ln(47/48)=2rlne==> ln(47/48)=2rlne=2r (since lne =1)
r= ln(47/48)/2==>r=-0.0210534/2 =-0.01052 ==> (r=-0.01052)
1) Determine when the value of the home will be 90% of its original value.
90% of 240000 =216,000
Now let's apply the formula
216,000=240,000,e^(-0.01052t), the unknown is t. Solving it by logarithm it will give t=10 years
1.a) Would the equation be set up like so: V=240e^.09t? NON, in any case if you solve it will find t=1 year
2)Determine the rate at which the value of the home is decreasing one year after : Already calculated above :(r=-0.01052)
3)The relative rate of change : it's r = -0.01052
1/4x^2 = -1/2x + 2.....multiply everything by 4
x^2 = -2x + 8
x^2 + 2x - 8 = 0
(x + 4)(x - 2) = 0
x + 4 = 0
x = -4
x - 2 = 0
x = 2
solutions are : x = -4 or x = 2
I am pretty sure the answer is the first box on the top right corner. Because vertical angles means they make an "X" shape, and that was the only one that did.
Answer:
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solution,
radius=7 in
Slant height=25 in
Volume of cone:
hope this helps...
Good luck on your assignment...