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andriy [413]
3 years ago
7

AYE HELP ME OUT GUYS!!! Question is the screen shot below

Mathematics
2 answers:
harkovskaia [24]3 years ago
7 0

Answer:

Pyramid

Step-by-step explanation:

let me know if you need explanation

AlekseyPX3 years ago
4 0

Answer:

pyramid  and cone i think

Step-by-step explanation:

hope this helps!

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Answer:

a) 10.47

b) 10.23

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Hello I need help<br> Find the missing side lengths, leave your answers as radicals in simplest form
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y =  \frac{1}{2}  \times  \frac{8 \sqrt{3} }{3}  \\

y = \frac{4 \sqrt{3} }{3}  \\

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x =  \frac{ \sqrt{3} }{2}  \times  \frac{8 \sqrt{3} }{3}  \\

x = \frac{8 \times  { \sqrt{3} }^{2} }{2 \times 3}  \\

x =  \frac{8 \times 3}{2 \times 3}  \\

x =  \frac{8}{2}  \\

x = 4

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4 0
3 years ago
Answer correct you get brainliest answer​
zloy xaker [14]

Answer:

y =  {x}^{2}  - 2

Or if you want with the value of h too.

y =  {(x - 0)}^{2}  - 2

Step-by-step explanation:

y = a {(x - h)}^{2}  + k

Find the value of h and k by using the formula.

h =  -  \frac{b}{2a}  \\ k =  \frac{4ac -  {b}^{2} }{4a}

From y = x²-2

a = 1 \\ b = 0 \\ c =  - 2

Substitute these values in the formula.

h =  -  \frac{0}{2(1)}  \\ h = 0

Therefore, h = 0.

k =  \frac{4(1)( - 2) -  {0}^{2} }{4(1)}  \\ k =  \frac{ - 8}{4}  \\ k =  - 2

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

y = a {(x - h)}^{2}  + k \\ y = 1 {(x - 0)}^{2}  - 2 \\ y =  {(x)}^{2}  - 2 \\ y =  {x}^{2}  - 2

These type of equation where b = 0 can also be both standard and vertex form.

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4 0
3 years ago
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