2 years ago

Which substance has a freezing point furthest from that of water, 0°C?

1 answer:

5 0

Answer:

The freezing point of water at a pressure of one atmosphere is 0°C (32°F); that of liquid nitrogen is -209.89°C (-345.8°F).

You might be interested in

How many times as heavy is the golden eagle as the northern bald eagle

alex41 [277]

Answer:

IDK but I need the points so

Step-by-step explanation:

7 0

2 years ago

I need some help lol

andrew-mc [135]

A veriable = 1, use it as with pemdas

5 0

2 years ago

What is the equation of the circle whose diameter has endpoints (8,-2) and (-2,6)?

klemol [59]

Answer:

$(x-3)^{2} +(y-2)^{2}=41$

Step-by-step explanation:

step 1

Find the diameter of the circle

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$A(8,-2)\\E(-2,6)$

substitute the values

$d=\sqrt{(6+2)^{2}+(-2-8)^{2}}$

$d=\sqrt{(8)^{2}+(-10)^{2}}$

$d=\sqrt{164}\ units$

$d=2\sqrt{41}\ units$

step 2

Find the center of the circle

The center is the midpoint of the diameter

The center is equal to

$C=(\frac{8-2}{2},\frac{-2+6}{2})$

$C=(3,2)$

step 3

Find the equation of the circle

The equation of the circle in center radius form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

we have

(h,k)=(3,2)

$r=2\sqrt{41}/2=\sqrt{41}\ units$ ---> the radius is half the diameter

substitute

$(x-3)^{2} +(y-2)^{2}=(\sqrt{41})^{2}$

$(x-3)^{2} +(y-2)^{2}=41$

4 0

3 years ago

Gina can buy a 5-pound bag of apples that cost $4.50, or she can buy them by the pound for $0.85 or pound. Which of these best e

sweet-ann [11.9K]

It's "D", because when you divide 4.5/5 you get .90 per pound so buying per pound it less.

5 0

3 years ago

What is the Y intercept of the function Y=(x+2) (x-4)

trasher [3.6K]

Answer:
Y=x^2-2x-8,x , x=r

5 0

2 years ago

Read 2 more answers