Answer:
Part 1 , not significant
Part II, significant
Step-by-step explanation:
Given that a heterozygous white-fruited squash plant is crossed with a yellow-fruited plant, yielding 200 seeds. of these seeds, 110 produce white-fruited plants while only 90 produce yellow-fruited plants
(Two tailed chi square test)
We assume H0 to be true and find out expected
If H0 is true expected would be 100 white and 100 yellow
Chi square = 
df = 1
p value = 0.152799
Since p value > 0.05 at 5% level we accept that the colours are equally likely
2)
Here observed are 1100 and 900
Expected 1000 & 1000
df = 1
Chi square = 
p value <0.0001
These results are here statistically significant.
Answer:
C <em>,</em><em> </em><em>negative</em><em> </em><em>two</em><em> </em><em>times</em><em> </em><em>a </em><em>number</em><em>,</em><em> </em><em>plus</em><em> </em><em>seven </em><em>,</em><em> </em><em>is </em><em>fewer</em><em> </em><em>than </em><em>twenty</em><em>-seven </em><em>and </em><em>five </em><em>tenths </em>
To solve this, since you know that h(x) is 11 and that it also equals -4x+3, you set them equal to one another which would look like this: 11=-4x+3.
Then, to solve for x, which is what I am assuming the question is asking, you would subtract 3 from both sides to isolate -4x, which would result in this:
-4x=8
Now, to solve for x, divide both sides by -4, and you get your answer which is x=-2
<span>Simplify: (d - 3)(d + 9)
A) d^2 + 6
B) d^2 - 27
C) d^2 - 12d - 27
D) d^2 + 6d - 27</span>
Jacob used 1/7 of a liter
of water.
He needs to fill 1/9 of the fish aquarium.
Find how many liters would Jacob need to fill the aquarium
=> Let x = liters of water need to fill the aquarium
=> x/1 = 1/7 divided by 1/9
=> x = 1/7 x 9/1
=> x = 9/7, since this is an improper fraction, let’s convert it to
mixed fraction
=> x = 1 and 2/7
So, Jacob need 1 and 2/7 liter of water to fill the whole aquarium.
