Please help thanks so much 20 points.

Hi if you have a 65% grade can a 80% bring it up to a C 70%

erma4kov [3.2K]

Answer:

Ask your Teacher if you are missing any work and if you are do it and do some things for extra credit

Step-by-step explanation:

5 0

2 years ago

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What is the answer to this question!?

vladimir2022 [97]

In your equation m=1

5 0

3 years ago

HELP ME EVERYONE PLZ

yawa3891 [41]

Answer:

Option D. 23.4 pounds

Step-by-step explanation:

step 1

Find the pieces of glass for 22.5 pounds of copper in the sculpture.

using proportion

$\frac{12}{1}=\frac{x}{22.5} \\ \\x=22.5*12\\ \\x=270\ piece\ of\ glass$

step 2

Find the pounds of bronze used in the sculpture

using proportion

$\frac{6.5}{75}=\frac{x}{270} \\ \\x=270*6.5/75\\ \\x=23.4\ pounds$

7 0

2 years ago

Solve the equation. show all work. 3x - 10 = 5x + 22

inysia [295]

Simplifying 3x + 10 = 5x + 22 Reorder the terms: 10 + 3x = 5x + 22 Reorder the terms: 10 + 3x = 22 + 5x Solving 10 + 3x = 22 + 5x Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-5x' to each side of the equation. 10 + 3x + -5x = 22 + 5x + -5x Combine like terms: 3x + -5x = -2x 10 + -2x = 22 + 5x + -5x Combine like terms: 5x + -5x = 0 10 + -2x = 22 + 0 10 + -2x = 22 Add '-10' to each side of the equation. 10 + -10 + -2x = 22 + -10 Combine like terms: 10 + -10 = 0 0 + -2x = 22 + -10 -2x = 22 + -10 Combine like terms: 22 + -10 = 12 -2x = 12 Divide each side by '-2'. x = -6 Simplifying x = -6

5 0

3 years ago

Situation:

Gala2k [10]

Answer:

5.5 days (nearest tenth)

Step-by-step explanation:

Given formula:

$\sf N=N_0e^{-kt}$

$\sf N_0$ = initial mass (at time t=0)
N = mass (at time t)
k = a positive constant
t = time (in days)

Given values:

$\sf N_0$ = 11 g
k = 0.125

Half-life: The time required for a quantity to reduce to half of its initial value.

To find the time it takes (in days) for the substance to reduce to half of its initial value, substitute the given values into the formula and set N to half of the initial mass, then solve for t:

$\begin{aligned}\sf N & = \sf N_0e^{-kt}\\\\\implies \sf \dfrac{11}{2} & = \sf 11e^{-0.125t}\\\\\sf \dfrac{1}{2} & = \sf e^{-0.125t}\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf \ln e^{-0.125t\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf -0.125t \ln e\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf -0.125t(1)\\\sf t & = \sf \dfrac{\ln \left(\dfrac{1}{2}\right)}{-0.125}\\\\\sf t & = \sf 5.545177444...\\\\\sf t & = \sf 5.5\:\:days\:\:(nearest\:tenth)\end{aligned}$

Therefore, the substance's half-life is 5.5 days (nearest tenth).

Learn more about solving exponential equations here:

brainly.com/question/28016999

5 0

1 year ago

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