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Agata [3.3K]
3 years ago
11

Help meee plssssssssssssssssssssssssssss

Mathematics
1 answer:
Drupady [299]3 years ago
3 0

Answer:

either a or c no problem nskskdjdjd

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WILL MARK YOU BRAINLIEST
Juli2301 [7.4K]
We know that the sum of all angle measures in a trapezoid is 360* (* means degrees)

Therefore we can construct the equation
(X+28)+(x)+(4x-14)+(4x-14)= 360

Now add like terms

10x = 360

And divide by the coefficient of X (aka 10)

X= 36
7 0
3 years ago
Please help solve this SAT math problem. I have 4 more like these so need help with this so that I can solve the rest by myself.
stealth61 [152]

The notation just means

(f/g)(-4) = f(-4) / g(-4)

If f(x) = x² + 2 and g(x) = 1 - 3x, then

f(-4) = (-4)² + 2 = 16 + 2 = 18

g(-4) = 1 - 3 (-4) = 1 + 12 = 13

and so

(f/g)(-4) = 18/13

8 0
3 years ago
What us the slope of this line
KIM [24]

Answer:

slope = \frac{1}{2}

Step-by-step explanation:

Calculate slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (0, - 2) and (x₂, y₂ ) = (4, 0) ← 2 points on the line

m = \frac{0-(-2)}{4-0} = \frac{0+2}{4} = \frac{2}{4} = \frac{1}{2}

6 0
3 years ago
find the equation of a cubic function whose graph passes through points (3,0) and (1,4) and is tangent to x-axis at the origin
Tomtit [17]

Answer:

y = -2x^2(x - 3)

Step-by-step explanation:

<em><u>Preliminary Remark</u></em>

If a cubic is tangent to the x axis at 0,0

Then the equation must be related to y = a*x^2(x - h)

<em><u>(3,0)</u></em>

If the cubic goes through the point (3,0), then the equation will become

0 = a*3^2(3 - h)

0 = 9a (3 - h)

0 = 27a - 9ah

from which h = 3

<em><u>From the second point, we get</u></em>

4 = ax^2(x - 3)

4 = a(1)^2(1 - 3)

4 = a(-2)

a = 4 / - 2

a = -2

<em><u>Answer</u></em>

y = -2x^2(x - 3)

 

3 0
3 years ago
A = 1/2ha +1/2hb solve for b
meriva

Answer:

A=1+1+2ha+2hb

A=2+2ha+2hb

A=2ha+2+2hb

A=<u>4ha</u>+<u>2hb</u>

4 = 4

A=½

3 0
3 years ago
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