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sineoko [7]
3 years ago
13

A study on the latest fad diet claimed that the amounts of weight lost by all people on this diet had a mean of 23.2 pounds and

a standard deviation of 6.6 pounds. Step 2 of 2 : If a sampling distribution is created using samples of the amounts of weight lost by 65 people on this diet, what would be the standard deviation of the sampling distribution of sample means
Mathematics
1 answer:
erica [24]3 years ago
3 0

Answer:

The standard deviation of the sampling distribution of sample means would be 0.8186.

Step-by-step explanation:

We are given that

Mean of population=23.2 pounds

Standard deviation of population=6.6 pounds

n=65

We have to find the standard deviation of the sampling distribution of sample means.

We know that standard deviation of the sampling distribution of sample means

=\frac{\sigma}{\sqrt{n}}

Using the formula

The standard deviation of the sampling distribution of sample means

=\frac{6.6}{\sqrt{65}}

=0.8186

Hence,  the standard deviation of the sampling distribution of sample means would be 0.8186.

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2 years ago
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guajiro [1.7K]

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2 years ago
Read 2 more answers
Mica bought a new smart phone for $258.13. That was the price after his 18.25% discount. What was the original price of the phon
julia-pushkina [17]

The original price of phone is $ 315.76

<em><u>Solution:</u></em>

Given that Mica bought a new smart phone for $ 258.13.

That was the price after his 18.25% discount

<em><u>To find: original price of phone</u></em>

From given question,

price after discount = $ 258.13

discount = 18.25 %

Let "x" be the original price of phone

price after discount = original price - discount

258.13 = x - 18.25 \% \text{ of } x

258.13 = x - \frac{18.25}{100}x

258.13 = x(1 - \frac{18.25}{100})

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Thus original price of phone is $ 315.76

4 0
3 years ago
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