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sineoko [7]
3 years ago
13

A study on the latest fad diet claimed that the amounts of weight lost by all people on this diet had a mean of 23.2 pounds and

a standard deviation of 6.6 pounds. Step 2 of 2 : If a sampling distribution is created using samples of the amounts of weight lost by 65 people on this diet, what would be the standard deviation of the sampling distribution of sample means
Mathematics
1 answer:
erica [24]3 years ago
3 0

Answer:

The standard deviation of the sampling distribution of sample means would be 0.8186.

Step-by-step explanation:

We are given that

Mean of population=23.2 pounds

Standard deviation of population=6.6 pounds

n=65

We have to find the standard deviation of the sampling distribution of sample means.

We know that standard deviation of the sampling distribution of sample means

=\frac{\sigma}{\sqrt{n}}

Using the formula

The standard deviation of the sampling distribution of sample means

=\frac{6.6}{\sqrt{65}}

=0.8186

Hence,  the standard deviation of the sampling distribution of sample means would be 0.8186.

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Wewaii [24]

Answer: 81.85 km/hr

Converting m/sec into km/hr, 25 m/sec = 90 km/hr

Average =

Time = 50/90  =  5/9 hr

next 120 km at an average speed of 80km/h

=> Time = 120/80  = 3/2  hr

last part of its journey at an average speed of 90km/h in 35 Minutes

time = 35 minutes = 35/60 hr = 7/12 hr

Distance covered = 90 * 7 /12  = 105/2  km

Total Distance = 50 + 120  + 105/2  = 435/2 km

Total time = 5/9 + 3/2 + 7/12   =  ( 20 + 54 + 21) /36  = 95/36

Average speed =   (435/2)/(95 /36)  = 432 * 18  /95 = 81.85 km/hr

8 0
3 years ago
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Margaret [11]

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8 0
3 years ago
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alexdok [17]

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Answer:

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3 years ago
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