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EleoNora [17]
3 years ago
5

I need to know how to solve ASAP!! Thanks!

Mathematics
2 answers:
Viktor [21]3 years ago
8 0

Answer:

x=24x

Step-by-step explanation:

Brainly

Nadusha1986 [10]3 years ago
4 0

Answer:

x = 10

Step-by-step explanation:

\frac{40}{55}  =  \frac{5x - 2}{6x + 6}  \\  \\ \frac{8}{11}  =  \frac{5x - 2}{6x + 6}  \\  \\ 8(6x + 6) = 11(5x - 2) \\  \\ 48x + 48 = 55x - 22 \\  \\ 48x - 55x =  - 22 - 48 \\  \\  - 7x =  - 70 \\  \\  x =  \frac{ - 70}{ - 7}  \\  \\ x = 10

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3 years ago
How many permutations are there of the letters in the words (a) TRISKAIDEKAPHOBIA (fear of the number 13)? (b) FLOCCINAUCINIHILI
zubka84 [21]

Answer: Hello!

Let's start with the word TRISKAIDEKAPHOBIA wich has 17 letters (some of them repeat, but it does not matter in this problem)

We want to know how many permutations we can do with 17 letters: then think this way, Lets compose a word. The first letter of this word has 17 options, the second letter of the word has 16 options (you already took one of the set) the third letter of the word has 15 options, and so on.

The total number of permutations is the product of the number of options that you have for each letter, this is:

17*16*15*14*....*3*2*1 = 17! = 3.6e+14

(b) FLOCCINAUCINIHILIPILIFICATION now we have 30 letters in total, using the same reasoning as before, here we have 30! permutations; this is

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6 0
3 years ago
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