We know that , in a circle radius perpendicular to chord will bisect the chord.
OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
This is a 30-60-90 right triangle with the shorter leg having a length of 5.
To find the length of x, we must find the length of the longer leg of the right triangle. To do that, we must multiply the shorter leg by the square root of 3.

This is the simplest radical form. Hope this helps! :)
That would be 1,132
Please mark me brainliest.
Answer:
used formula to find Area of parallelogram
area of parallelogram =b× h
Step-by-step explanation:
solution :
given ,
h = 7cm
b = 9 cm
we know ,
Area of parallelogram = b× h
=63cm²