In short, (h o g)(a) is just h( g(a) ).
so what we can do is simply get g(a) first and then plug that in h(x).
so what we can do is simply get g(a) first and then plug that in h(x).
ein rechteckiger Bauplatz ist 39,5 m lang und 32,5 m breit . wie teuer ist der Grund ,wenn ein Quadratmeter Bauland 185,50 euro
1 answer:
So first you need to find the area of the building site which is:
length x width
39.5m x 32.5m
= 1283.75
We know that one square meter costs 185.50 euros.
1 = 185.50 euros
1283.75 = <u>238135.625 euros</u>
I'm not exactly that familiar with euros but I'm pretty sure that euros don't have 3 numbers after the point so the two nearest numbers are <u>238134.86 and 238135.86.</u>
sorry if this is wrong, but I hope it helps, if the euros part is wrong please correct me thanks!
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This question is incomplete, the complete question is;
The owners of Spiffy Lube want to offer their customers a 10-minute guarantee on their standard oil change service. If the oil change takes longer than 10 minutes to complete, the customers is given a coupon for a free oil change at the next visit. Based on past history, the owners believe that the timer required to complete an oil change has a normal distribution with a mean of 8.6 minutes and a standard deviation of 1.2 minutes.
Suppose management could improve the process by reducing the mean time required for an oil change (but keeping the standard deviation the same). How much change in the mean service time would be required to allow for a 10-minute guarantee that gives a coupon to no more than 1 out of every 25 customers on average
Answer:
Required change in the mean service time is 7.8988
Step-by-step explanation:
Given the data in the question;
How much change in the mean service time would be required to allow for a 10-minute guarantee that gives a coupon to no more than 1 out of every 25 customers on average
let mean = μ
p( x > 10 ) ≤ (1/25)
p( x > 10 ) ≤ 0.4
p( x-μ / 1.2 > 10-μ / 1.2 ) ≤ 0.4
(10-μ / 1.2 ) ≤ 0.4
(10-μ / 1.2 ) ≥ ( 0.96 )
(10-μ / 1.2 ≥ 1.751
10-μ = ≥ 1.751 × 1.2
10-μ ≤ 2.1012
μ ≤ 10 - 2.1012
μ ≤ 7.8988
Therefore, required change in the mean service time is 7.8988