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3 years ago

Choose a value for B so that the relation below is not a function

Mathematics

1 answer:

mariarad [96]3 years ago

7 0

Answer:2

Step-by-step explanation:

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An agency that hires out clerical workers claims its workers can type, on average, at least 60 words per minute (wpm). To test t

Zanzabum

Answer:

D.) If the mean typing speed of workers from the agency is 60 wpm, the probability of selecting a sample of 50 workers with mean 58.8 wpm or less is 0.267.

Step-by-step explanation:

In this case, the p value is what let's us determine the probability of getting the desired outcome. This would be 60 wpm.

If it is lower than the desired outcome, we know that this inference is not the <em>actual mean </em>of the data.

3 0

3 years ago

Read 2 more answers

52. What is the 275th digit after the decimal point in the

Xelga [282]

The right answer is k :).
Hope you have a nice day

3 0

3 years ago

Help please.. question in the file.

Alex787 [66]

-1/2+2 (-9/4)
Reduce the fraction by dividing the numerator and denominator by 2
-1/2+1 (-9/2)
Multiply the values
-1/2 - 9/2
Bring the values to the common denominator
(-1-9)/2
Calculate the difference
-10/2
Reduce the fraction by dividing the numerator and denominator by 2
-5.

7 0

4 years ago

What is the value of X?

rodikova [14]

Answer:

102

Step-by-step explanation:

triangle area = 180 degrees

straight line = 180 degrees

180 - 127 = 53

49 + 53 + 3rd angle = 180

3rd angle = 78

180-78 = x

x = 102

4 0

3 years ago

It is estimated that t-weeks into a semester, the average amount of sleep a college math student gets per day S(t) decreases at

goldenfox [79]

Answer:

s(15)= $\frac{-3}{2} e^{15^{2} } +9.6$

Step-by-step explanation:

Before to getting started ,we have to consider the function which represents sleep decline rate S'(t) = $-3te^{t^{2} } \\$

Since this function is interpreted in this case as a rate of change, we can deduce this funcion is the first derivative of the function of average amount of sleep (S(t)).

In order to find S(t), we will integrate S'(t)

$\int\limits^ {} -3t3e^{t^{2} } \, dx \\$

This case corresponds to intergration by substitution

Substituting u= $x^{2} \\$

Computting the differential of u

$\frac{du}{dt} =2tdt\\$

Now, let's go back to our integral and write it in terms of u, using both definition of u and its defferential.

$\int\limits^{}-3te^{u} \, \frac{1}{2t}du \\\\\int\limits^{}\frac{-3}{2} e^{u}du\\$

The integral of a exponential function is itself. So the result is:

$\frac{-3}{2} e^{u} +c$

Now substitute u back in:

$\frac{-3}{2} e^{t^{2} } +c$

This answer correspond to function of average amount of sleep.

We know that when the semester begins (t=0) , math students sleep an average of 8.1 hours per day so we will use this info in order to find the value of c.

$s(0)=\frac{-3}{2} e^{0^{2} } +c=8.1\\\\\frac{-3}{2} +c=8.1$

Solve this equation

c=8.1+ $\frac{3}{2}$

c=9.6

Replacing the value of c on S(t)

S(t)= $\frac{-3}{2} e^{t^{2} } +9.6$

Now, let's to find the average of amount of sleep when 15 weeks has elapsed since the start date of the semester.

s(15)= $\frac{-3}{2} e^{15^{2} } +9.6$

4 0

3 years ago