Find the circumference of the circle. round your answer to the nearest centimeter.

From 12:00 midnight to 6:00am, the

olga nikolaevna [1]

Answer:

A. 12-12

Step-by-step explanation:

Becuase if the temperature was originally 12°C then it decreases by 12° then it will be 12-12

5 0

3 years ago

Read 2 more answers

Over which interval(s) is g(x) = x2 + x - 12 positive?

VikaD [51]

Answer:

B. x < -4 and x > 3

Step-by-step explanation:

Factor and set = to 0

$x^{2} + x - 12\\( x + 4)(x - 3)$ = 0

x = - 4 or x = 3 I call these critical values

The two numbers would divide a number line into 3 intervals. Pick a value in one of the intervals and put it in the original expression. If it makes the function positive, then all the values in that interval make the function positive. If the value you picked makes the function negative, then the values in the other intervals will make the function negative. Let's pick the value of 0 and substitute it into the function

We get $0^{2}$ + 0 - 12 = -12 which is not positive. Therefore, all the values between -4 and 3 will make the function negative. So, the values less than -4 or greater than 3 will make the function positive. Therefore, B is the correct answer.

Another way to do this problem is to graph the function and see where the graph is above the x-axis. But, sometimes it is not easy to graph the function.

4 0

3 years ago

A swimming pool is circular with a 40-ft diameter. The depth is constant along east-westlines and increases linearly from 2 ft a

AnnZ [28]

Answer:

volume will be equal to 5,655 ft³

Step-by-step explanation:

diameter of swimming pool = 40 ft

depth increases from east-west lines is from 2 ft to 7 ft

so the average depth of the swimming pool can be calculated by

$D_{avg} = \frac{2+7}{2}$

hence average depth comes out to be 4.5 m

volume of water in the pool will be equal to the volume of the pool

volume = $\pi\times r^2 \times d_{avg}$

= $\pi\times 20^2 \times 4.5$

= 5,654.86 ft³

volume will be equal to 5,655 ft³ approximately

6 0

4 years ago

Simplify sin θ / square root 1 - sin^2 θ

Soloha48 [4]

Recall that

$\cos^2\theta+\sin^2\theta=1$

which means

$\dfrac{\sin\theta}{\sqrt{1-\sin^2\theta}}=\dfrac{\sin\theta}{\sqrt{\cos^2\theta}}$

Now, $\cos\theta$ could be positive or negative, which means $\sqrt{\cos^2\theta}=|\cos\theta|$ . If we specifically knew the sign of $\cos\theta$ was positive, then we can simplify and write