So for me, how I would do it is move the variables and numbers to one side. So we have the equation 3x-3=2/5x+7. So you would subtract 2/5x to the left side and add 3 to the right side. The equation will then turn out to be 3x-2/5x=7+3. Much more easier right? So just simplify both side, and you will get 13/5x=10. In order to isolate x, you have to divide 13/5 in both side, leaving x= 3 11/13 or 50/13. You can always plug the answer back in to double check :)

5 0

3 years ago

5x( 4y2 + 5z) – (4y2 + 52

mrs_skeptik [129]

Hello! :)

To solve your equation, we will simplify

5 x (4y^2 + 5z) - (4y^2 +52)

Let's Distribute the negative sign

5 x (4y^2 + 5z) + −1 (4y^2 + 52)

5x (4y^2 + 5z) + −1 (4y^2) + (−1) (52)

5x (4y^2 + 5z) + −4y^2 + −52

Now, we will Distribute

(5x) (4y2)+(5x) (5z) + -4y^2 + -52

20xy^2 + 25xz + −4y^2 + −52

Hope this helped you!

THEDIPER

3 0

4 years ago