How many quarts of pure antifreeze must be added to 8 quarts of a 10% antifreeze solution to obtain a 60% antifreeze solution
1 answer:
Answer:
10 quarts
Step-by-step explanation:
.1(8) + 1(x) = .6(x + 8)
.8 + x = .6x + 4.8
.4x = 4
x = 10
10 quarts
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replace M with S-3 to get:
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2S=78
s=39
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