Question 1:
Since this is an isosceles trapezoid angle J is equal to angle M
20x + 9 = 14x + 15
Subtract both sides by 14x and 9
6x = 6
Divide both sides by 6
x = 1
Plug this into 14x + 15 and 20x + 9
You get 29 degrees.
Now, multiply that by 2.
29 * 2 = 58
Subtract that from 360 to get the sum of angles K and L
360 - 58 = 302
Now, divide that by 2 since we know that angles K and L are congruent.
302 / 2 = 151
That's the measure for both angle K and L.
The first choice is your answer.
Question 2:
The diagonals of a rhombus are always perpendicular. That means angles 1, 2, and 3 are all equal to 90 degrees.
Although it may seem that we'll have to solve for x, y, and z. We really only need to solve for z.
For angle 2, we know that x + y = 90.
Now, let's solve for z.
30z = 90
Divide both sides by 30
z = 3
Now, add them all together
x + y + z
= 90 + 3
= 93
The first choice is your answer.
Question 3:
The diagonals of a rectangle are always congruent.
6x + 16 = 49
Subtract both sides by 16
6x = 33
Now, divide both sides by 6
x = 5.5
The last choice is your answer.
Have an awesome day! :)
Answer:
1/3, -7
Step-by-step explanation:
Before answering this, I will need to assume that you actually meant
y = (1/3)x - 7. Comparing this to y = mx + b, we see that the slope, m, is 1/3 and the y-intercept, b, is -7.
-2x +7 = 3x - 8
Move the variable to the left-hand side and change its sign
-2x -3x+ 7 = -8
Move the constant to the right-hand side and change its sign
-2x -3x = -8 -7
Collect like terms
-5x = -15
Divide both sides of the equation by -5
x=3
Answer:
see below
Step-by-step explanation:
a)
minimum = 45
first quartile = 55
median = 75
third quartile = 85
maximum = 95
lower fence = Q1 - 1.5 x IQR = 10
upper fence = Q3 + 1.5 x IQR = 130
Therefore, one outlier = 140
b) mean = sum of all numbers ÷ n = 760 ÷ 10 = 76 ($76,000)
There is an outlier (140). Outliers don't affect the median as much as they affect the mean.
c) see attached
d) negative skew
