I wish I did I would help u out but I hope u have luck
<span>$220
000 is the total cost of the house that a buyer bought.
Prior to that, he paid 10% of the amount for down payment.
Now, we need to find the amount he will need to pay to paid off the house he
bought.
=> 10% = 10 / 100
=> 0.1
We already have the value of 10%, now multiply this to the total amount of the
house
=> 220 000 x 0.1
=> 22 000 – he paid this amount for down payment.
Now, let’s subtract his down payment from the total amount.
=> $220 000 – 22 000
=> $198 000
Thus, the home buyer will pay 198 000 to paid off the house he bought.
</span>
Answer:
x = 1
Step-by-step explanation:
hope it helps uwu
WY = a = 4
ZY = b = 3
As WYZ is forming a right angle triangle, therefore, we can use pythagorean theorem to find the value of c
a2+b2=c2 (4)2+(3)2=C2 16+9=C2 C2=25
Taking square root on both sides
√c2= √25 c=5
The value of c is 5 units.
Answer with explanation:
Relation between Speed , Distance and time
Distance =Speed × Time
→It means Speed is inversely Proportional to time.
As distance will remain constant , in that frame of reference
If speed of light in a Medium
![=s=3 \times 10^8 \frac{\text{meter}}{\text{second}}](https://tex.z-dn.net/?f=%3Ds%3D3%20%5Ctimes%2010%5E8%20%5Cfrac%7B%5Ctext%7Bmeter%7D%7D%7B%5Ctext%7Bsecond%7D%7D)
Then, time taken to cross the medium = t seconds or hours or another unit of time.
Now, If speed of light is 50% of the speed of light relative to us
That is Speed of light in another medium
![=w=\frac{50}{100} \times 3 \times 10^8\\\\=1.5 \times 10^8 \frac{\text{meter}}{\text{second}}](https://tex.z-dn.net/?f=%3Dw%3D%5Cfrac%7B50%7D%7B100%7D%20%5Ctimes%203%20%5Ctimes%2010%5E8%5C%5C%5C%5C%3D1.5%20%5Ctimes%2010%5E8%20%5Cfrac%7B%5Ctext%7Bmeter%7D%7D%7B%5Ctext%7Bsecond%7D%7D)
Then, time taken to cross the medium = 2t seconds or hours or another unit of time.
Using Unitary Method
![\rightarrow v_{1}\times t_{1}=v_{2} \times t_{2}\\\\1.\rightarrow 3 \times 10^8 \times t=\frac{50}{100} \times 3 \times 10^8 \times t_{1}\\\\t_{1}=2t\\\\2.\rightarrow 3 \times 10^8 \times t=\frac{99.5}{100} \times 3 \times 10^8 \times t_{2}\\\\t_{2}=\frac{1000t}{995}\\\\t_{2}=\frac{200t}{199}](https://tex.z-dn.net/?f=%5Crightarrow%20v_%7B1%7D%5Ctimes%20t_%7B1%7D%3Dv_%7B2%7D%20%5Ctimes%20t_%7B2%7D%5C%5C%5C%5C1.%5Crightarrow%203%20%5Ctimes%2010%5E8%20%5Ctimes%20t%3D%5Cfrac%7B50%7D%7B100%7D%20%5Ctimes%203%20%5Ctimes%2010%5E8%20%5Ctimes%20t_%7B1%7D%5C%5C%5C%5Ct_%7B1%7D%3D2t%5C%5C%5C%5C2.%5Crightarrow%203%20%5Ctimes%2010%5E8%20%5Ctimes%20t%3D%5Cfrac%7B99.5%7D%7B100%7D%20%5Ctimes%203%20%5Ctimes%2010%5E8%20%5Ctimes%20t_%7B2%7D%5C%5C%5C%5Ct_%7B2%7D%3D%5Cfrac%7B1000t%7D%7B995%7D%5C%5C%5C%5Ct_%7B2%7D%3D%5Cfrac%7B200t%7D%7B199%7D)