That is 19 divided by 4. Hope that helped!
Answer:
10 and 12
Step-by-step explanation:
let the consecutive even integers be n and n + 2 , then
n² - 64 = 3(n + 2) ← distribute parenthesis
n² - 64 = 3n + 6 ( subtract 3n + 6 from both sides )
n² - 3n - 70 = 0 ← in standard form
(n - 10)(n + 7) = 0 ← in factored form
Equate each factor to zero and solve for n
n - 10 = 0 ⇒ n = 10
n + 7 = 0 ⇒ n = - 7
Since n must be a positive even integer then n = 10 and n + 2 = 10 + 2 = 12
The 2 numbers are 10 and 12
Answer:
−
4
x
^2
−
3
x
−
5
Step-by-step explanation:
Answer:
The product would be -40a^7b^4
Step-by-step explanation:
In order to find this, we first need to expand the parenthesis with the power.
(-2a^2b)^3 = 8a^6b^3
Now we can take the expanded form and multiply it by the other term.
8a^6b^3 * 5ab = -40a^7b^4