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3 years ago

I HAD TO PUT IN MATH BUT ITS PE

Mathematics

1 answer:

natka813 [3]3 years ago

5 0

Get your body in position.

Make sure to keep your eyes on the front of the rim before you shot and while you shoot.

Keep your shooting arm parallel to the rim when you shoot the ball.

Bend your knees!

Shoot the ball off your finger tips.

Make sure to follow through with your shot!

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Given: 3 − 2(x + 4) = 13 prove: x = −9

Brums [2.3K]

Answer:

I hope this helps:))

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Which statement correctly compares the mean number of students for the data in the plots?

satela [25.4K]

Answer:

"There are about 2 more students in each class at Oak Middle School than at Poplar Middle School."

Step-by-step explanation:

We need to compute the mean for each.

Poplar Middle School:

Lets list the numbers

20,20,20,21,21,21,21,21,22,22,22,22,22,22,22,23,23,23,23,24

The average is sum of all divided by number of numbers, that will be:

435/20 = 21.75

Oak Middle School:

The numbers are:

20,21,21,22,22,23,23,23,23,24,24,24,25,25,26,26,27,27,28,29

The average is sum divided by number of numbers, that will be:

483/20 = 24.15

The difference in mean is:

24.15 - 21.75 = 2.4

We can say, that is about 2 more students in Oak Middle School, correct answer choice is "2nd answer choice" - "There are about 2 more students in each class at Oak Middle School than at Poplar Middle School."

7 0

3 years ago

find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM

Snezhnost [94]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - A trapezium ABCD with non parallel sides of measure 15 cm each ! along , the parallel sides are of measure 13 cm and 25 cm

To find - Area of trapezium

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

Construction -

$draw \: CE \: \parallel \: AD \: \\ and \: CD \: \perp \: AE$

Now , we can clearly see that AECD is a parallelogram !

$\therefore$ AE = CD = 13 cm

Now ,

$AB = AE + BE \\\implies \: BE =AB - AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm$

Now , In ∆ BCE ,

$semi \: perimeter \: (s) = \frac{15 + 15 + 12}{2} \\ \\ \implies \: s = \frac{42}{2} = 21 \: cm$

Now , by Heron's formula

$area \: of \: \triangle \: BCE = \sqrt{s(s - a)(s - b)(s - c)} \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)} \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21} \: cm {}^{2}$

Also ,

$area \: of \: \triangle \: = \frac{1}{2} \times base \times height \\ \\\implies 18 \sqrt{21} = \: \frac{1}{\cancel2} \times \cancel12 \times height \\ \\ \implies \: 18 \sqrt{21} = 6 \times height \\ \\ \implies \: height = \frac{\cancel{18} \sqrt{21} }{ \cancel 6} \\ \\ \implies \: height = 3 \sqrt{21} \: cm {}^{2}$

Since we've obtained the height now , we can easily find out the area of trapezium !

$Area \: of \: trapezium = \frac{1}{2} \times(sum \: of \:parallel \: sides) \times height \\ \\ \implies \: \frac{1}{2} \times (25 + 13) \times 3 \sqrt{21} \\ \\ \implies \: \frac{1}{\cancel2} \times \cancel{38 }\times 3 \sqrt{21} \\ \\ \implies \: 19 \times 3 \sqrt{21} \: cm {}^{2} \\ \\ \implies \: 57 \sqrt{21} \: cm {}^{2}$

hope helpful :D

6 0

2 years ago

A fish with 68 meters at a constant speed in 8 minutes. On her homework assignment, Tracy said the fish traveled 60 meters per m

Natasha2012 [34]

Morgan is right because to find how much something is per minute you need to divide. In this case, you need to divide 68 and 8. The answer then is 8.5

3 0

3 years ago

Solve the equation 1/4y+9=1/2

malfutka [58]

Answer:

y = -34

Step-by-step explanation:

Step 1

1/4 y + 9 = 1/2

1/4 + 9 - 9 = 1/2 - 9

1/4 y = -17/2

Step 2

4 * (1/4 y) = 4* (-17/2)

y = -34

Hope this helps!!

7 0

3 years ago