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k0ka [10]
3 years ago
5

Erica has a bowl of skittles that has 5 red skittles for every 25 skittles. What percent of her skittles are red?

Mathematics
2 answers:
9966 [12]3 years ago
4 0
5/25 = x/100
cross multiply and get 25x = 500
solve for x and get x = 20
20% is red
mr Goodwill [35]3 years ago
3 0

Answer:

20%

Step-by-step explanation:

if you wouldn't mind giving me brainliest, i'm just trying to rank up.

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Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br
aliya0001 [1]

Answer:

A=1500-1450e^{-\dfrac{t}{250}}

Step-by-step explanation:

The large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved.

Volume = 500 gallons

Initial Amount of Salt, A(0)=50 pounds

Brine solution with concentration of 2 lb/gal is pumped into the tank at a rate of 3 gal/min

R_{in} =(concentration of salt in inflow)(input rate of brine)

=(2\frac{lbs}{gal})( 3\frac{gal}{min})\\R_{in}=6\frac{lbs}{min}

When the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

Concentration c(t) of the salt in the tank at time t

Concentration, C(t)=\dfrac{Amount}{Volume}=\dfrac{A(t)}{500}

R_{out}=(concentration of salt in outflow)(output rate of brine)

=(\frac{A(t)}{500})( 2\frac{gal}{min})\\R_{out}=\dfrac{A}{250}

Now, the rate of change of the amount of salt in the tank

\dfrac{dA}{dt}=R_{in}-R_{out}

\dfrac{dA}{dt}=6-\dfrac{A}{250}

We solve the resulting differential equation by separation of variables.  

\dfrac{dA}{dt}+\dfrac{A}{250}=6\\$The integrating factor: e^{\int \frac{1}{250}dt} =e^{\frac{t}{250}}\\$Multiplying by the integrating factor all through\\\dfrac{dA}{dt}e^{\frac{t}{250}}+\dfrac{A}{250}e^{\frac{t}{250}}=6e^{\frac{t}{250}}\\(Ae^{\frac{t}{250}})'=6e^{\frac{t}{250}}

Taking the integral of both sides

\int(Ae^{\frac{t}{250}})'=\int 6e^{\frac{t}{250}} dt\\Ae^{\frac{t}{250}}=6*250e^{\frac{t}{250}}+C, $(C a constant of integration)\\Ae^{\frac{t}{250}}=1500e^{\frac{t}{250}}+C\\$Divide all through by e^{\frac{t}{250}}\\A(t)=1500+Ce^{-\frac{t}{250}}

Recall that when t=0, A(t)=50 (our initial condition)

50=1500+Ce^{-\frac{0}{250}}50=1500+Ce^{0}\\C=-1450\\$Therefore the amount of salt in the tank at any time t is:\\A=1500-1450e^{-\dfrac{t}{250}}

4 0
3 years ago
Um litro de suco é dividido entre três amigos. O primeiro fica com 14 do todo, o segundo fica com 1/3 do total e o terceiro fica
kkurt [141]

Answer:

a) 1/24 do total

Step-by-step explanation:

We have that:

The total is 1.

The first friend gets 1/4 of the total.

The second friend gets 1/3 of the total

The third friend gets 3/8 of the total.

The remaining is x.

So

\frac{1}{4} + \frac{1}{3} + \frac{3}{8} + x = 1

The least common multiple between 4, 3 and 8 is 24. So

\frac{6 + 8 + 3*3 + 24x}{24} = 1

23 + 24x = 24

24x = 1

x = \frac{1}{24}

So the correct answer is:

a) 1/24 do total

3 0
3 years ago
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