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Nataliya [291]
3 years ago
15

My friend didn’t do this and he got another question ASAP

Mathematics
1 answer:
AysviL [449]3 years ago
4 0

Answer: B.) I and II

Step-by-step explanation: remember doing this in like- middle school so you're welcome! it should be the right answer(:

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(2*2)^2-(3+(2*2)/(6-4) EXPLAINED PLEASE
Eva8 [605]

PEMDAS is an acronym that refers to the sequence of operations to be employed when solving equations with multiple operations. The solution of the given expression (2×2)² - [3+(2×2)]/(6-4) is 14.

<h3>What is PEMDAS?</h3>

PEMDAS is an acronym that refers to the sequence of operations to be employed when solving equations with multiple operations. PEMDAS is an acronym that stands for P-Parenthesis, E-Exponents, M-Multiplication, D-Division, A-Addition, and S-Subtraction.

As per the rule of PEMDAS, the given expression can be simplified as shown below.

(2×2)² - [3+(2×2)]/(6-4)

Step 1: Solving Parenthesis,

= 4² - (3+4) / (2)

= 4² - 4/2

Step 2: Solving exponents,

= 16 - 4/2

Step 3: Solving Divisions,

= 16 - 2

Step 4: Solving Subtraction,

= 14

Hence, the solution of the given expression (2×2)² - [3+(2×2)]/(6-4) is 14.

Learn more about PEMDAS here:

brainly.com/question/36185

#SPJ1

6 0
1 year ago
Which property of addition is shown below?
natta225 [31]
Inverse property is being shown
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2 years ago
Trent can deliver his newspapers in 4040 minutes. It takes Lois 1010 minutes to do the same route. How long would it take them t
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25 minutes. hope this helps ^_^
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3 years ago
If the boolean expression a is true and b is false, the value of the logical expression a and b is ________.
makkiz [27]
<span>false The truth table for the and function is Inputs output a b t/f f f f f t f t f f t t t which shows that the and function is only true if and only if both of its inputs are true. Since b is false, then the value of the function a and b is false.</span>
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Charra [1.4K]

Answer:

<h2>6</h2>

Step-by-step explanation:

\sqrt{a}=b\iff b^2=a\ for\ a\geq0\ and\ b\geq0\\\\\\\sqrt5-not\ rational\\\\\sqrt8-not\ rational\\\\\sqrt{36}=6-rational\qquad(\sqrt{36}=6\ because\ 6^2=36)\\\\\sqrt{44}-not\ rational

3 0
3 years ago
Read 2 more answers
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