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inysia [295]
2 years ago
13

Can someone help me do this question?

Mathematics
2 answers:
olasank [31]2 years ago
7 0

3(-2x-1)=2(x+5)

-6x-3=2x+10

-8x=13

x=-13/8

Sonbull [250]2 years ago
7 0
X=5 I kind of did this by trail and error but here’s my working outs
5-4=1
3/1=3
5-2=3
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NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t)=−4.9t2+121t
Alenkasestr [34]

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by

h(t)=-4.9t^2+121t+283

The sea level is represented by h = 0, therefore, to find the corresponding time when h splashes into the ocean we have to solve for t the following equation:

h(t)=0\implies-4.9t^2+121t+283=0

Using the quadratic formula, the solution for our problem is

\begin{gathered} t=\frac{-(121)\pm\sqrt{(121)^2-4(-4.9)(283)}}{2(-4.9)} \\ =\frac{121\pm142.083778...}{9.8} \\ =\frac{121+142.083778...}{9.8} \\ =26.8452834694... \end{gathered}

The rocket splashes after 26.845 seconds.

The maximum of this function happens at the root of the derivative. Differentiating our function, we have

h^{\prime}(t)=-9.8t+121

The root is

-9.8t+121=0\implies t=\frac{121}{9.8}=12.347

Then, the maximum height is

h(12.347)=1029.99

1029.99 meters above sea level.

6 0
1 year ago
The equation of the line pass through the points (-4,2) and (-5,2) is
ivanzaharov [21]

Answer:

  y = 2

Step-by-step explanation:

Both points are on the horizontal line ...

  y = 2

__

<em>Additional comment</em>

A horizontal line has equation y = constant. A vertical line has equation x = constant.

7 0
2 years ago
Read 2 more answers
Write 1. 995x10^-22 in standard form.
densk [106]
That would be 177.5 in standard form.
5 0
3 years ago
Hi, Could anyone help me with my homework
tatiyna

Answer:

\hookrightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

solving steps:

\rightarrow \sf (x + 4)^6

\bold{rewrite \ the \ following}

\rightarrow \sf (x + 4)^2   (x + 4)^2   (x + 4)^2

\bold {formula \ used : \sf  (x+a)^2 = (x^2 + 2xa + a^2)}

\rightarrow \sf (x^2 + 8x+16)    (x^2 + 8x+16)    (x^2 + 8x+16)

\bold{simplify \ by  \ removing \ parenthesis}

\rightarrow \sf (x^4 +8x^3 + 16x^2 + 8x^3 +64x^2 + 128x+16x^2+128x+256 ) (x^2 + 8x+16)

\bold{basic \ addition \ of \ integers }

\rightarrow \sf (x^4+16x^3+96x^2+256x+256) (x^2 + 8x+16)

\bold{remove \ parenthesis}

\rightarrow \sf (x^6 + 16x^5 + 96x^4 + 256x^3 + 256x^2 + 8x^6 + 128x^4 + 768x^3 + 2048x^2 + 2048 + 16x^4 + 256x^3 + 1536x^2 + 4096x + 4096)

\bold {final \ answer:}

\rightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

8 0
2 years ago
Use the method of Gauss-Jordan elimination (trails—forming (lie augmented matrix into reduced echelon form) to solveProblem in S
Nezavi [6.7K]

Answer:

Step-by-step explanation:

Answer is in below attachment

7 0
3 years ago
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