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olchik [2.2K]
3 years ago
7

Two trains leave the station at the same time, one heading east and the other west. The eastbound train travels at 70 mph. The w

estbound train travels at 90 mph. How long will it take for the two trains to be 192 miles apart.
Mathematics
1 answer:
Iteru [2.4K]3 years ago
4 0

Answer:

1.2 hours

Step-by-step explanation:

Recall :

Distance = speed * time

Let the time taken = x

Creating an equation for the question :

Distance of train A + Distance of train B = 192

70 * x + 90 * x = 192

70x + 90x = 192

160x = 192

x = 192 / 160

x = 1.2

It takes 1.2 hours to be 192 miles apart.

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What is the solution to this equation?<br><br> 8x - 5 (x-3) = 18
Kaylis [27]

Answer:

x=1

Step-by-step explanation:

We distribute the negative 5 to x minus three to get 8x-5x+15=18. Then, we cancel out the 15 by subtracting it from both sides. This leaves us with 8x-5x=3. When we subtract, we get 3x=3, and when we divide both sides by 3, we get x=1. Hope this helps :)

3 0
3 years ago
Evaluate the variable expression x + y for the given values of x and y . X=43.37 ; Y=18.24
cupoosta [38]

Answer:

61.61

Step-by-step explanation:

In the expression now that we know the value of x and y, we can replace it with its values. So it would look like this.... 43.37 + 18.24. This equals 61.61.

Hope this helps!

4 0
3 years ago
Pregnancy length (in days) is a normally distributed random variable with a mean of 266 days and a standard deviation of 16 days
velikii [3]

Answer:

it=552

Step-by-step explanation:

with rounding it = 550

5 0
2 years ago
Please help! I don't understand how to solve this problem
Ilia_Sergeevich [38]

Using the z-distribution, a sample of 142,282 should be taken, which is not practical as it is too large of a sample.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

The margin of error is:

M = z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

Assuming an uniform distribution, the standard deviation is given by:

S = \sqrt{\frac{(4 - 0)^2}{12}} = 1.1547

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

The sample size is found solving for n when the margin of error is of M = 0.006, hence:

M = z\frac{\sigma}{\sqrt{n}}

0.006 = 1.96\frac{1.1547}{\sqrt{n}}

0.006\sqrt{n} = 1.96 \times 1.1547

\sqrt{n} = \frac{1.96 \times 1.1547}{0.006}

(\sqrt{n})^2 = \left(\frac{1.96 \times 1.1547}{0.006}\right)^2

n =  142,282.

A sample of 142,282 should be taken, which is not practical as it is too large of a sample.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

8 0
1 year ago
At the beginning of the month Leslie's parents put $35.00 on her account. If lunch costs $2.55 per day, how much money would be
Annette [7]

Answer:

$73.25

Step-by-step explanation:

35 + 2.55(15) = 38.25 + 35 = 73.25

6 0
3 years ago
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