30 x 24 there you gooooooo
Answer: The common number is 26.
Step-by-step explanation:
We know that the n-th term of a sequence is:
aₙ = 3*n^2 - 1
And the n-th term of another sequence is:
bₙ = 30 - n^2
Remember that in a sequence n is always an integer number.
We want to find a number that belongs to both sequences, then we want to find a pair of integers x and n, such that:
aₙ = bₓ
This is:
3*n^2 - 1 = 30 - x^2
Let's isolate one of the variables, i will isolate n.
3*n^2 = 30 - x^2 + 1 = 31 - x^2
n^2 = (31 - x^2)/3
n = √( (31 - x^2)/3)
Now we can try with different integer values of x, and see if n is also an integer.
if x = 1
n = √( (31 - 1^2)/3) = √10
We know that √10 is not an integer, so we need to try with another value of x.
if x = 2:
n = √( (31 - x^2)/3) = √(27/3) = √9 = 3
Then if we have x= 2, n is also an integer, n = 3.
Then we have:
a₃ = b₂
The common number between both sequences is:
a₃ = 3*(3)^2 - 1 = 26
b₂ = 30 - 2^2 = 26
Answer:
C
Step-by-step explanation:
Given that the 2 triangles are similar then the ratios of corresponding sides are equal.
This enables RT to be found, that is
= 
( cross- multiply )
4RT = 60 ( divide both sides by 4 )
RT = 15
Hence
perimeter of ΔRST = 6 + 12 + 15 = 33 units
Answer:
(x-y)(x-y-1)
Step-by-step explanation:
1.(x - y)² - x + y = (x - y)² - (x - y )
2.(x-y) [( x-y) - ( 1 ) ]
3.(x-y)(x-y-1)
Answer:
cge
Step-by-step explanation:
