Answer:
17.03
Step-by-step explanation:
Just searched it up, if its wrong my bad
Each ream weighs 5 lb . so, reducing 10 lb means removing 2 reams from the 12. so, how do we arrange the 10 reams so that its easy to carry?
i thinks that 3 stacks will not work as it wont be a symmetric arrangement as 1 will be left out. So, 2 stacks of 5 each would be easy to carry. but the stacks should be placed in such a way that the lengths are parallel to each other and not in-line which would increase the length making it comparatively longer. its easier to hold a (2*8.5,11,2*5=17,11,17)compact box.
50/8 can be simplified by dividing top and bottom by 2, getting 25/4. this is also equal to 6 and 1/4
Answer and Step-by-step explanation: The <u>critical</u> <u>value</u> for a desired confidence level is the distance where you must go above and below the center of distribution to obtain an area of the desired level.
Each sample has a different degree of freedom and critical value.
To determine critical value:
1) Calculate degree of freedom: df = n - 1
2) Subtract the level per 100%;
3) Divide the result by 2 tails;
4) Use calculator or table to find the critical value t*;
For n = 5 Level = 90%:
df = 4
t = = 0.05
Using t-table:
t* = 2.132
n = 13 Level = 95%:
df = 12
t = = 0.025
Then:
t* = 2.160
n = 22 Level = 98%
df = 21
t = = 0.01
t* = 2.819
n = 15 Level = 99%
df = 14
t = = 0.005
t* = 2.977
The critical values and degree of freedom are:
sample size level df critical value
5 90% 4 2.132
13 95% 12 2.160
22 98% 21 2.819
15 99% 14 2.977