Answer:
10
Step-by-step explanation:
d = 10
For:
(X1, Y1) = (13, 2)
(X2, Y2) = (7, 10)
Distance Equation Solution:
d=(7−13)2+(10−2)2−−−−−−−−−−−−−−−−−√
d=(−6)2+(8)2−−−−−−−−−−√
d=36+64−−−−−−√
d=1–√00
d=10
Answer:
x = 7
Step-by-step explanation:
5x - 2 + x = 9 + 3x + 10
6x - 2 = 9 + 3x + 10
6x - 2 = 3x + 19
6x = 3x + 21
3x = 21
x = 7
the parallel line is 2x+5y+15=0.
Step-by-step explanation:
ok I hope it will work
soo,
Solution
given,
given parallel line 2x+5y=15
which goes through the point (-10,1)
now,
let 2x+5y=15 be equation no.1
then the line which is parallel to the equation 1st
2 x+5y+k = 0 let it be equation no.2
now the equation no.2 passes through the point (-10,1)
or, 2x+5y+k =0
or, 2*-10+5*1+k= 0
or, -20+5+k= 0
or, -15+k= 0
or, k= 15
putting the value of k in equation no.2 we get,
or, 2x+5y+k=0
or, 2x+5y+15=0
which is a required line.
M to the power 4 squared minus 23
